Answer: The heat required to melt 25.0 g of ice at 
is 8350 Joules
Explanation:
Heat of Fusion tells us how much energy is needed to convert 1g of a solid to a liquid at the same temperature.
Q = Heat absorbed = ?
m = mass of ice = 25.0 g
L = Latent heat of fusion of ice = 334 J/g
Putting in the values, we get:
Thus heat required to melt 25.0 g of ice at is 8350 Joules
Answer:
Buffer is the chemical substance that addition of acids and bases, maintaining constant environment,its called Buffer.
Explanation:
- Buffers are use in the system to maintain the value of pH, and the contain the pH value is not to change.
- Buffer maintain the body of pH for the optimal activity,and they are solution of pH constant.
- Buffer in used in the lab and that to maintain growth of the micro tissues and the culture media.
- Buffer are used in maintain necessary optimal reaction activity,determine the indicator of solution with pH.
- Buffer capacity is that concentration to the buffering agent, is the very small increase,buffer capacity to the pH is 32% , of the maximum value of pH.
- Buffers in a acid regions to the desired of that value to the particular buffer agent.
- Buffers can be made from that a mixture of the base and acid, buffer can be a wide range of the obtained.
- Buffers that the pH calculation and they required to performed in the critic acid that the overlap over the buffer range.
Answer:
The initial volume of Ne gas is 261mL
Explanation:
This question can be answered using Ideal Gas Equation;
However, the following are the given parameters
Initial Pressure = 654mmHg
Finial Pressure = 345mmHg
Final Volume = 495mL
Required
Initial Volume?
The question says that Temperature is constant;
This implies that, we'll make use of Boyle's law ideal gas equation which states;
Where 
represent the initial pressure
represent the final pressure
represent the initial temperature
represent the final temperature
Substitute these values in the formula above;
Divide both sides by 654
(Approximated)
<em>The initial volume of Ne gas is 261mL</em>
Here you are looking on the Free Body diagram of a net force of 0N in both the x and y-directions. the only ones that has that condition met is A and C.
1. Convert gallons to mL. 1 gal = 3785.4117840007 mL, multiply that by 29 and get 109776.94173602 mL.
2. Since there is one gram per every mL, there are 109776.94173602 g of water in the fish tank.
3. Convert g to pounds. 1 g = 0.0022 pounds. Multiply 109776.94173602 by 0.0022 and end up with about 241.5 pounds of water.
