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Olenka [21]
3 years ago
15

Lead + Nitric Acid discplacment

Chemistry
1 answer:
jeyben [28]3 years ago
6 0

Answer: According to research

Lead when reacted with nitric acid forms lead (II) nitrate, nitrogen oxide and water

Explanation:

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4. Synthesis problems. Propose a synthetic route from the starting material to the product. In your answer, show each individual
Troyanec [42]

The reduction of alkyne to an alkene in the first step allows the best reagent to be chosen for each subsequent step.

Describe reagents.

A reagent is merely an essential component of a chemical reaction, it should be mentioned. It is an ingredient that speeds up the reaction.

With H2 and Lindlar's catalyst, an alkyne is reduced to alkene as the initial step in this process. Alkene will then be brominated to produce allyl bromide as the next step.

In this instance, the required allyl alcohol will be produced via the reaction of allyl bromide with NaOH.

Learn more about reagent here brainly.com/question/23342137

#SPJ4.

5 0
2 years ago
A buffer solution is composed of 7.50 mol of acid and 4.75 mol of the conjugate base. If the pKa of the acid is 4.90 , what is t
Mamont248 [21]

Answer:

The correct answer is: pH= 4.70

Explanation:

We use the <em>Henderson-Hasselbach equation</em> in order to calculate the pH of a buffer solution:

pH= pKa + log   \frac{ [conjugate base]}{[acid]}

Given:

pKa= 4.90

[conjugate base]= 4.75 mol

[acid]= 7.50 mol

We calculate pH as follows:

pH = 4.90 + log (4.75 mol/7.50 mol) = 4.90 + (-0.20) = 4.70

7 0
3 years ago
-- A scientist combines 14 grams of potassium nitrate with an unknown amount of
igor_vitrenko [27]

Answer:

The unknown amount of potassium chloride is 13.6 grams.            

 

Explanation:

The reaction of 14 grams of KNO₃ with KCl produces a total mass of 27.6 grams of the products.

The law of conservation of mass tells us that the total mass of the reactants must be the same that the total mass of the products. So, we can find the mass of KCl as follows:

m_{r} = m_{p}

Where <em>r</em> is for reactants and <em>p </em>is for products

m_{KNO_{3}} + m_{KCl} = m_{p}

14 g + m_{KCl} = 27.6 g

m_{KCl} = 27.6 g - 14 g = 13.6 g

Therefore, the unknown amount of potassium chloride is 13.6 grams.           

I hope it helps you!

5 0
3 years ago
How many grams of potassium nitrate (KNO3) are required to prepare 0.250L of a 0.700 M
CaHeK987 [17]

Answer:

17.78g

Explanation:

m/M = C×V

m/101.102= 0.7× 0.25

m= 101.102×0.7×0.25= 17.78g

6 0
3 years ago
HELP! help will give brainiest
ivolga24 [154]
I believe it’s Fatigue
6 0
3 years ago
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