All categories

3 years ago

Explain why increasing the mass of a car affects how the car rolls down a ramp.

Physics

2 answers:

Finger [1]3 years ago

6 0

Answer:

Q1) Explain why increasing the mass of a car affects how the car rolls down a ramp

Ans1) Weight affects speed down the ramp but it's the mass that affects speed after a car leaves the ramp. Heavier cars have more momentum, so they travel further, given the same amount of friction

Irina-Kira [14]3 years ago

4 0

F = ma (force = mass x acceleration)

So the car’s mass affects the amount of force, changing how it would roll down a ramp, I think.

You might be interested in

What kinds of bonds are possible between carbon and oxygen?

ikadub [295]

<span>covalent bond I think </span>

5 0

4 years ago

At what water temperature will additional heat energy need to be added before the temperature will change again?

Katyanochek1 [597]

That would be 0 degrees Celsius aka the melting point of water.... If you look at the diagram I attached you notice that at 0 degrees Celsius it is flat, this is because much heat is needed at this point for water to rise to 1 degree... It is the same for the boiling point (100)

Hope this helps! (If correct, please rank as brainliest answer) :)

7 0

3 years ago

WHAT STEPS CAN YOU TAKE IF YOU BEEN A VICTIM OF ASSAULT

AfilCa [17]

Answer:

If you have a parental figure or guardian ask them for assistance. Contact a lawyer if you are willing to take action against your attacker.

3 0

3 years ago

Compare these two collisions of a PE student with a wall.

Stolb23 [73]

1) The variable that is different in the two cases is $\Delta t$ , the duration of the collision

2) The change in momentum is the same in the two cases

3) The impulse is the same in the two cases

4) Case B will experience a greater force

Explanation:

The variable that is different in the two cases is $\Delta t$ , the duration of the collision.

In fact, in the first case the wall is padded: this means that the collision will be "softer" and therefore will last longer, so the duration of the collision, $\Delta t$ , will be larger.

In the second case instead, the wall is unpadded: this means that the collision is "harder" and so it will last less time, therefore the duration of the collision $\Delta t$ will be smaller.

The change in momentum in the two cases is the same.

In fact, the change in momentum is given by:

$\Delta p = m(v-u)$

where:

m is the mass of the student

u is the initial velocity

v is the final velocity

In both cases, we have:

m = 75 kg

u = 8 m/s

v = 0 (they both comes to rest)

Therefore, the change in momentum is

$\Delta p = (75)(0-8)=-600 kg m/s$

The impulse in the two cases is the same.

In fact, impulse is defined as the product of force applied, F, and duration of the collision, $\Delta t$ :

$J=F \Delta t$

However, the force can be rewritten as product of mass (m) and acceleration (a), according to Newton's second law:

$F=ma$

So the impulse is

$J=ma\Delta t$

The acceleration can be rewritten as rate of change of velocity:

$a=\frac{\Delta v}{\Delta t}$

So the impulse becomes

$J=m\frac{\Delta v}{\Delta t}\Delta t = m\Delta v$

So, the impulse is equal to the change in momentum: and since in the two cases the change in momentum is the same, the impulse is the same as well.

The force in the collision is related to the impulse by

$J=F\Delta t$

where

J is the impulse

F is the force

$\Delta t$ is the duration of the collision

The equation can be rewritten as

$F=\frac{J}{\Delta t}$

In the two situations described in the problem (A and B), we already said that the impulse is the same (because the change in momentum is the same). However, in case A (padded wall) the time $\Delta t$ is longer, while in case B (unpadded wall) the time $\Delta t$ is shorter: since the force F is inversely proportional to the duration of the collision, this means that in case B the student will experience a greatest force compared to case A.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

3 0

4 years ago

Angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes (the):

Vsevolod [243]

Angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes the line focus principle

<h3>What is the line focus principle?</h3>

The line focus principle states that as the anode angle is reduced, the actual focal spot also becomes small but the heat loading is increased.

It also explains the relationship between the anode surface and the effective focal spot size.

As a result of this, by angling the target, effective area of the target is made much smaller that the actual area of electron interaction.

Hence, angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes the line focus principle.

Learn more about line focus principle here:

#SPJ1

3 0

2 years ago