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sveta [45]
3 years ago
7

Lim x → ∞ (12x^8-3)/3x^8-2x^7

Mathematics
1 answer:
emmainna [20.7K]3 years ago
8 0

Divide through all terms by the highest power of x:

\dfrac{12x^8-3}{3x^8-2x^7}=\dfrac{12-\frac3{x^8}}{3-\frac2x}

As x\to\infty, the terms with x in the denominator will vanish, leaving us with

\displaystyle\lim_{x\to\infty}\frac{12x^8-3}{3x^8-2x^7}=\frac{12}3=4

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