Answer:
Complete combustion of 0.1mol of monocarboxylic acid requires V litres of O2 at dtc. and the reaction produces 0.3mol of CO2 and 0.2mol of H2O.
What is the value of V?
Explanation:
The balanced chemical equation of the reaction is

1mol. of acid reacts with 1mol of
and produce 2mol. of CO2 and 2mol. of H2O.
Given,
0.1mol of acid requires how many litres of oxygen at STP?
0.1mol of acid requires 0.1mol of oxygen.
Since, 1mol of oxygen at STP occupies 22.4L of volume.
Hence, the volume occupied by 0.1mol of oxygen is -- 2.24L
Answer is:
The value of V is 2.24L.
Answer:
The atomic number of Selenium is 34. This means that Selenium possesses 34 electrons.
The atomic number of Aluminium is 13. This means that Aluminium has 13 electrons.
Hence, there is a difference of 21 between the number of electrons in an atom of selenium and the number of electrons in an atom of aluminium.
Selenium has 6 electrons in it's outer most shell whereas aluminium has 3 electrons in its outer most shell. As a result, aluminium will have a greater tendency to lose one of its outer most electrons to become stable.
Answer:
It would get <u>colder</u>
Explanation:
The lattice energy is the energy involved in the disruption of interactions between the ions of the salt. In this case, we have: ΔHlat = 350 kJ/mol > 0, so it is an endothermic process (the energy is absorbed).
The solvation energy is the energy involved in forming interactions between water molecules and the ions of the salt. In this case, we have: ΔHsolv = 320 kJ/mol > 0, so it is an endothermic process (the energy is absorbed).
The dissolution process involve both processes: the disruption of ion-ion interactions of the salt and the solvation process. Thus, the enthalphy change (ΔHsol) in the preparation of the solution is calculated as the addition of the lattice energy and solvation energy:
ΔHsol= ΔHlat + ΔHsolv = 350 kJ/mol + 320 kJ/mol = 370 kJ/mol
370 kJ/mol > 0 ⇒ endothermic process
Since the preparation of the solution is an <u>endothermic</u> process, it will absorb energy from the surroundings, so <u>the solution would get colder</u>.