I think the answer is prescriptions
Calculate the pressure due to sea water as density*depth.
That is,
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa
Atmospheric pressure is 101.3 kPa
Total pressure is 94423 + 101.3 = 94524 kPa (approx)
The area of the window is π(0.44 m)^2 = 0.6082 m^2
The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
Suppose earth is a soid sphere which will attract the body towards its centre.So, acc. to law of gravitation force on the body will be,
F=G*m1m2/R^2
but we now that F=ma
and here accleration(a)=accleration due to gravity(g),so
force applied by earth on will also be mg
replace above F in formula by mg and solve,
F=G*mE*m/R^2 ( here mE is mass of earth and m is mass of body)
mg=G*mEm/R^2
so,
g =G*mE/R^2
The spring constant of the given spring is 250 N/m. Spring constant is the measure of the stiffness of the spring.
<h3>
What is the spring constant?</h3>
It is the measure of the stiffness of the spring or in other work how much a spring resists the deformation.
From Hooke's law,
- force - 75 N
- spring constant
- displacement - 0.3 m
Put the values in the formula and calculate for ,
Therefore, the spring constant of the given spring is 250 N/m.
Learn more about spring constant:
brainly.com/question/4291098