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3 years ago

A- what constant acceleration, in SI units, must a car have to gofrom zero to 60 mph in 10 s?

Physics

2 answers:

lorasvet [3.4K]3 years ago

4 0

Answer:

a) acceleration a = 2.68 m/s^2

b) fraction of g = 0.273 or 27.3%

c) distance travelled d = 134m (in SI unit)

d = 439.5ft (in feet)

Explanation:

a) converting 60mph (miles per hour) to m/s

∆v = 60 miles/hour × 1609.344meters/mile × 1/3600 seconds/hour

∆v = 26.82m/s

t = 10s

acceleration = change in velocity/time = ∆v/t

Acceleration a = 26.82/10 = 2.68m/s^2

b) acceleration due to gravity is g = 9.8m/s^2

Fraction of g = a/g = 2.68/9.8 = 0.273

Fraction = 0.273 or 27.3%

c) distance travelled can be calculated using the equation below.

d = ut + 0.5at^2 ....1

Initial speed u = 0

time t = 10s

Acceleration a = 2.68m/s^2

d = distance covered.

From equation 1, putting u = 0

d = 0.5at^2

d = 0.5(2.68 × 10^2)

d = 134m

Converting meters to feet

d = 134m × 3.28ft/m

d = 439.5ft

umka2103 [35]3 years ago

3 0

Answer:

(a) 0.017m/s^2

(b) 17/100,000

Explanation:

(a) speed = 60mph = 60m/1h × 1h/3600s = 0.017m/s, time = 10s

Acceleration (a) = speed ÷ time = 0.017m/s ÷ 10s = 0.0017m/s^2

(b) g = 9.8m/s^2, a = 0.0017m/s^2

a/g = 0.0017/9.8 = 0.00017 = 17/100,000

Distance in foot = 0.17 × 3.2808ft = 0.558ft

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A Block slides down an incline that makes an angle of 30? with the horizontal direction. The coefficient of kinetic friction bet

astraxan [27]

Answer:

Acceleration = 2.35 m/ $s^{2}$

Speed = 8.67 m/s

Explanation:

The coefficient of friction , u =0.3

The angle of incline = 30°

The two forces acting on block are weight and friction.

weight along the incline = mg cos60° = $\frac{mg}{2}$ = 0.5 mg

Friction along incline = umg cos30° = mg $0.3\times \frac{\sqrt{3}}{2}$

Friction along incline = 0.26 mg

Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg

Acceleration = $\frac{net force}{mass}$ = 0.24 g = 2.35 m/ $s^{2}$

The height of incline = 8 m

Length of the inclined edge = 16 m

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$v^{2}= 2\times 0.24 \times 9.8\times 16$

v= 8.67 m/s

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3 years ago

When you apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed ().When you apply a f

elena-s [515]

Answer:

Explanation:

When we apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed. So net force on the block is zero .

It implies that a force ( frictional ) acts on it which is equal to 76 N in opposite direction ( friction )

When we apply a greater force on it it starts moving with acceleration .

This time kinetic friction acts on it due to rough ground equal to 76 N .This is limiting friction ( maximum friction )

Net force on the body in later case

= 89 - 76

= 13 N

Force by ground on the block in horizontal direction = 76 N ( FRICTIONAL FORCE )

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3 years ago

Can someone help me please??

Mrrafil [7]

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3 years ago

There is a species of bamboo that can grow 36 inches per day. If a plant grew at this rate and was measured at 40 inches initial

LekaFEV [45]

Answer:

It will take the plant $4\frac{4}{9}$ days or 4.44 days to grow to a height of 200 inches tall.

Explanation:

From the question, the rate at which the species of the bamboo tree grows is 36 inches per day.

To determine how long it would take a plant 40 inches tall initially to grow at this rate (that is, 36 inches per day) to a height of 200 inches.

This means we will calculate the number of days it will take the plant to grow additional 160 inches ( 200 inches - 40 inches) at this rate.

Now,

If the plant grows 36 inches in 1 day

then it will grow 160 inches in x days

x = (160 inches × 1 day) / 36 inches

x = 160 / 36

x = $4\frac{4}{9}$ days or 4.44 days

Hence, it will take the plant $4\frac{4}{9}$ days or 4.44 days to grow to a height of 200 inches tall.

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3 years ago

To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeof

il63 [147K]

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