Answer:
12.62 L
Explanation:
First, we have to calculate the moles corresponding to 18.0 g of oxygen gas (MW 32.0).
18.0 g × (1 mol/32.0 g) = 0.563 mol
Then, we can find the volume occupied by 0.563 moles of oxygen at STP (273,15 K, 1.00 atm) using the ideal gas law.
P × V = n × R × T
V = n × R × T / P
V = 0.563 mol × 0.0821 atm.L/mol.K × 273.15 K / 1.00 atm
V = 12.62 L
To correct her measurement to standard temperature and pressure (STP), she must <span>make a volume correction based on a higher temperature of 273 K. The answer is letter B. This is in order to correct the temperature and pressure because correcting the volume will indicate that the temperature and pressure will result to the opposite result of the volume. This is because volume is indirectly proportional with pressure and temperature.</span>
Answer:
All the options are correct except "has 7 electrons"
Explanation:
The answer to this question is 1s^2.
Answer:
16.56g.
Explanation:
You need to compare the number of coefficient of the reaction product to find how much water produced. The reaction formula will produce 6 carbon dioxide(CO2) and 6 water (H2O).
If the reaction produces 0.92 moles of carbon dioxide, then the amount of water produced in moles will be: 0.92 moles * (6/6)= 0.92 moles
The molar mass of water is 18g/mol, so the calculation of moles to mass will be: 0.92 moles * (18g/mol)= 16.56g.
