What units must be used for v?Ek = _ x m x v2
1 answer:
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F=nmv
where;
n=no. of bullets = 1
m=mass of bullets=2g *10^-3
V=velocity of bullets200m/sec
F=1
loss in Kinetic energy=gain in heat energy
1/2MV^2=MS∆t
let M council M
=1/2V^2=S∆t
M=2g
K.E=MV^2/2
=(2*10^-3)(200)^2/2
2 councils 2
2*10^-3*4*10/2
K.E=40Js
H=mv∆t
(40/4.2)
40Js=40/4.2=mc∆t
40/4.2=2*0.03*∆t
=158.73°C
Answer:
Explanation:
According to Coulomb's law, the magnitude of the electric force between two point charges is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
Here k is the Coulomb constant. In this case, we have ,
and
. Replacing the values:
The negative sign indicates that it is an attractive force. So, the magnitude of the electric force is:
1) First of all, let's find the resistance of the wire by using Ohm's law:
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
2) Now that we have the value of the resistance, we can find the resistivity of the wire
by using the following relationship:
Where A is the cross-sectional area of the wire and L its length.
We already have its length
, while we need to calculate the area A starting from the radius:
And now we can find the resistivity:
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
2) Now that we have the value of the resistance, we can find the resistivity of the wire
Where A is the cross-sectional area of the wire and L its length.
We already have its length
And now we can find the resistivity: