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3 years ago

A charge of 9 pC is uniformly distributed throughout the volumebetween concentric spherical surfaces having radii of 1.6 cmand

Physics

1 answer:

balu736 [363]3 years ago

7 0

Answer:

Electric Field = 3.369 x 10^4 N/C

Explanation:

Radius = r = (r1 + r2) / 2 = (1.6 + 3.6) /2 = 2.6 cm + 2.3 cm = 4.9 cm = 0.049 m

As we know, Electric field = E = kQ/r.r

= 8.98755 x 10^9 x 9 x 10^-9 / 0.049 x 0.049 = 33689.275 N/C

= 3.369 x 10^4 N/C

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An object at 27°C has its temperature increased to 37°C.

Firlakuza [10]

Answer:

b. 14

Explanation:

$T_{i}$ = Initial temperature = 27 °C = 27 + 273 = 300 K

$T_{f}$ = Final temperature = 37 °C = 37 + 273 = 310 K

$P_{i}$ = Initial Power radiated by the object

$P_{f}$ = Final Power radiated by the object

We know that the power radiated is directly proportional to fourth power of the temperature. hence

$\frac{P_{f}}{P_{i}} = \frac{T_{f}^{4} }{T_{i}^{4} }\\\frac{P_{f}}{P_{i}} = \frac{(310)^{4} }{(300)^{4} }\\\frac{P_{f}}{P_{i}} = 1.14\\P_{f} = (1.14) P_{i}$

Percentage increase in power is given as

$\frac{(P_{f} - P_{i})\times100}{P_{i}} \\\frac{((1.14) P_{i} - P_{i})\times100}{P_{i}} \\14$

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3 years ago

An object has an initial velocity of 15 m/s. How long must it accelerate at a constant rate of 3.0 m/s^2 before its final veloci

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Answer: v=u + at

V= Final velocity =30m/s

U= initial velocity = 15m/s

a= acceleration = 3m/s^2

t= time taken

t=(v-u)/a

t=(30-15)/3

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Explanation:

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3 years ago