I believe it is either vaporization or boiling someone might need to correct me on it.
Answer:
The approximate molar enthalpy of combustion of this substance is -66 kJ/mole.
Explanation:
First we have to calculate the heat gained by the calorimeter.

where,
q = Heat gained = ?
c = Specific heat = 
ΔT = The change in temperature = 3.08°C
Now put all the given values in the above formula, we get:


Now we have to calculate molar enthalpy of combustion of this substance :

where,
= enthalpy change = ?
q = heat gained = 8.2544kJ
n = number of moles methane = 

Therefore, the approximate molar enthalpy of combustion of this substance is -66 kJ/mole.
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Plastics and polysaccharides are somewhat similar because they are both polymers. Polymers are a long chain of repeating units called monomers. Their difference, however, is the identity of their monomers. Plastics have hydrocarbons as monomers. Plastics with the monomer ethene is called polyethylene. For polysaccharides, their monomers are simple sugars.