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Aleksandr-060686 [28]
2 years ago
14

do you think it is likely that major volcanic eruption will occur on the mainland of the united states​

Chemistry
2 answers:
andre [41]2 years ago
3 0

Answer:

yes

Explanation:

Oxana [17]2 years ago
3 0

Answer:

It would be very unlikely that a volcanic eruption will occur in the mainland (Midwest or surrounding) to occur.

Explanation:

The nearest platonic plates are in California in the triangle with Japan and China, the chances of earthquakes are also low in this area due to the fact that no plates could collide to produce an earthquake, or form a volcano.

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mrs_skeptik [129]

Answer:

0.414 mole (3 sig. figs.)

Explanation:

Given grams, moles = mass/formula weight

moles in 18.2g CO₂(g) = 18.2g/44g/mole = 0.413636364 mole (calc. ans.)

≅ 0.414 mole (3 sig. figs.)

6 0
2 years ago
Enthalpy of combustion of ethyl alcohol, C2 H5 OH, is – 950 kJ mol–1. How much heat is evolved when one gram of ethyl alcohol bu
melomori [17]
<h3>Answer:</h3>

20.62 Kilo-joules

<h3>Explanation:</h3>
  • The Enthalpy of combustion of ethyl alcohol is -950 kJ/mol.
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Molar mass of ethyl ethanol = 46.08 g/mol

Therefore;

46.08 g of  C₂H₅OH evolves heat equivalent to 950 kilojoules

We can calculate the amount of heat evolved by 1 g of C₂H₅OH

Heat evolved by 1 g of C₂H₅OH  = Molar enthalpy of combustion ÷ Molar mass

                                      = 950 kJ/mol ÷ 46.08 g/mol

                                      = 20.62 Kj/g

Therefore, a gram of C₂H₅OH  will evolve 20.62 kilo-joules of heat

7 0
2 years ago
How many atoms are in 1.75 mol CHCL3
vaieri [72.5K]

1 mol = 6.022 x 10²³ atoms

In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.

So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃

But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃

6 0
3 years ago
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Answer:

A : 1

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6 0
3 years ago
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Reil [10]

Answer:False

Explanation:co2 or carbon dioxide is a  compound not an element, you can even check this on the periodic table

7 0
3 years ago
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