<span>The solid lines between N and Mg are actually ionic bonds. N has 5 valence electrons (2 of which are paired). Of the 3 that are unpaired, 2 are part of covalent bonds with adjacent carbon atoms. N accepts an extra electron to complete its octet, but gets a formal charge of -1. This allows for formation of an ionic bond with Mg, which is +2. Two of these charged N atoms therefore neutralize the charge of the central Mg. As for the coordinate (dative) covalent bonds, Mg has empty orbitals - the ionic bonds with the charged N atoms give it only 4/8 possible valence electrons.
The other two N atoms (dotted lines) have a formal charge of 0 since they form three covalent bonds with adjacent carbon atoms, but they still have a lone pair. Therefore, just to improve stability, each of these N atoms can "donate" its lone pair to Mg in order to complete its octet.
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Answer:
3.329 g
Explanation:
First you need to determine the molar mass of H2S which is 34.1 g/mol.
With that we know that to find the moles of H2S we just divide the mass of sample with the molar mass.
3.54 g / 34.1 g/mol = 0.103812317 mol of H2S
This means that there is also 0.103812317 mol of sulfur since there is 1 mole of sulfur per 1 mole of H2S.
The molar mass of sulfur is 32.065 g/mol and to find the mass of sulfur you need to multiply the molar mass with the moles of the compound.
0.103812317 mol * 32.065 g/mol = 3.329 g of sulfur
Let me know if you get something else or if something is unclear in the comments so that we can figure it out.
