Give the ground state electron configuration for lead
1 answer:
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Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Answer:
<h3>The answer is 1.99 g/mL</h3>Explanation:
The density of a substance can be found by using the formula
From the question
mass = 16.93 g
volume = final volume of water - initial volume of water
volume = 19.7 - 11.2 = 8.5 mL
We have
We have the final answer as
<h3>1.99 g/mL</h3>Hope this helps you