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ololo11 [35]
3 years ago
13

Which statement best explains how the models differ? Model A shows the formation of ions, and model B does not show the formatio

n of ions. Model A does not show the formation of ions, and model B shows the sharing of electrons. Model A shows the sharing of electrons, and model B shows the formation of ions. Model A shows the transfer of an electron, and model B shows the sharing of electrons.
Chemistry
2 answers:
creativ13 [48]3 years ago
8 0

Answer) Model A shows the sharing of electrons, and model B shows the formation of ions.

enot [183]3 years ago
8 0

Answer: C

Explanation:

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What is the mass of 1 atom?
VLD [36.1K]

6.7 mass because 1 atom equals 6.3 but if u add 4 it would be 6.7

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2 years ago
Reaction of hypochlorous acid and ammonia is product-favored system at equilibrium. Answer A: Reaction of hypochlorous acid and
pickupchik [31]

Answer:

A. True

B. False

Explanation:

Reaction between hypochlorous acid and ammonia does not yields a Ph value of 7.00 , this value is defined to water and no other reaction can yield exactly this Ph value. The acid reaction will give a Ph value below 7 while a base reaction will give Ph value of above 7.

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An atom has the following electron configuration 1s2s2sp63s23p64s2 How many valance electrons does this atom have?
JulijaS [17]

Answer:

The electron configuration for this atom is Calcium, which has 2 valence electrons.

Explanation:

Following the periodic table and with the electron configuration, you will end up with calcium, which has 2 valence electrons. (Always follow the electron configuration from left to right! It begins at hydrogen, then to helium... and so on.)

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6 0
3 years ago
A student dissolves of urea in of a solvent with a density of . The student notices that the volume of the solvent does not chan
Dimas [21]

The question incomplete , the complete question is:

A student dissolves of 18.0 g urea in 200.0 mL of a solvent with a density of 0.95 g/mL . The student notices that the volume of the solvent does not change when the urea dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to significant digits.

Answer:

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

Explanation:

Moles of urea = \frac{18.0 g}{60 g/mol}=0.3 mol

Volume of the solution = 200.0 mL = 0.2 L (1 mL = 0.001 L)

Molarity(M)=\frac{\text{Moles of compound}}{\text{Volume of solution in L}}

Molarity of the urea solution ;

M=\frac{0.3 mol}{0.200 L}=1.50 M

Mass of solvent = m

Volume of solvent = V = 200.0 mL

Density of the urea = d = 0.95 g/mL

m=d\times V=0.95 g/mL\times 200.0 mL=190 g

m = 190 g = 190 \times 0.001 kg = 0.19 kg

(1 g = 0.001 kg)

Molality of the urea solution ;

Molality(m)=\frac{\text{Moles of compound}}{\text{Mass of solvent in kg}}

m=\frac{0.3 mol}{0.19 kg}=1.58 m

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

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3 years ago
What is a serial dilution?
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A serial dilution is the stepwise dilution of a substance in solution. Usually the dilution factor at each step is constant, resulting in a geometric progression of the concentration in a logarithmic fashion.

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3 years ago
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