1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sweet [91]
3 years ago
14

A 15.9 g sample of sodium Carbonate is added to a solution of acetic acid weighing 20 g. the 2 substances react, releasing carbo

n dioxide gas to the atmosphere and water. after reaction, the contents of the reaction vessel weighs 29.3 g. what mass of carbon doixide was released into the atmosphere during the reaction?​
Chemistry
1 answer:
adell [148]3 years ago
3 0

Answer:

hope that helps

Explanation:

The total mass of reactants taken = 15.9 + 20.0 = 35.9 gm. From the conservation of mass the final mass of the contents of the vessel should also be 35.9 gm. But it is only 29.3 gm. The difference is due to the mass of released carbon dioxide gas.Hence the mass of carbon dioxide gas released = 35.9 – 29.3 = 6.6 gm

You might be interested in
Calculate the molarity of sodium ion in a solution made
Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Moles =Molarity \times {Volume\ of\ the\ solution}

Sodium chloride will furnish Sodium ions as:

NaCl\rightarrow Na^{+}+Cl^-

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

Moles =0.288 \times {3.58\times 10^{-3}}\ moles

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}

<u> The final concentration of sodium anion = 0.1035 M</u>

4 0
3 years ago
What is the value of the activation energy of the uncatalyzed reaction?
Lubov Fominskaja [6]
The value of the activation energy of an uncatalyzed reaction is greater than that of a catalyzed reaction. As we know, a catalyst provides an alternative path for the reaction to happen at a faster rate. So, for a catalyzed reactio, activation energy is lesser than the original path.
6 0
3 years ago
Calculate Ho298 for the process
Inga [223]

Explanation:

As per the Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

Hence, according to this law the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Sb + \frac{3}{2}Cl_2 \rightarrow SbCl_{3}    \Delta H^0_1 =  -314 kJ  ..........(1)

SbCl_{3} + Cl_2 \rightarrow SbCl_{5}    \Delta H^0_2 = -80kJ   ..............(2)

The final reaction is as follows:  

Sb + \frac{5}{2}Cl_{2} \rightarrow SbCl_{5}  \Delta H^0_3 = ?  .............(3)

Therefore, adding (1) and (2) we get the final equation (3) and value of \Delta H^{0}_{3} at 298 K will be as follows.

             \Delta H^{0}_{3} = \Delta H^{0}_{1} + \Delta H^{0}_{2}    

                       = -314 kJ + (-80) kJ

                       = -394 kJ

Thus, we can conclude that H^{o} at 298 K for the given process is -394 kJ.

4 0
3 years ago
Flag question
Ghella [55]

Answer:

B sediment

Explanation:

The excess mileage leads to additional pollution. Car exhaust contains toxic gases, and car fluids often leak (oil drips, antifreeze leaks, etc...). The exhaust also contains nitrogen oxide, which can lead to nutrient-related problems in the environment.

3 0
3 years ago
Read 2 more answers
if you could count individual atoms at the rate of one per second, about how many years would be required to count 6.02x10^23 at
Arte-miy333 [17]
Roughly 19,089,294,774,226,281 years
3 0
3 years ago
Other questions:
  • Eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
    7·1 answer
  • How is it possible to have thousands of different proteins when there are only 20 different amino acids?
    5·1 answer
  • From his experiments, J. J. Thomson concluded that
    7·2 answers
  • Frost is dew that forms when the air temperature is______
    8·2 answers
  • For each of the following sublevels, give the n and l values and the number of orbitals: (a) 5s; (b) 3p; (c) 4f
    7·1 answer
  • Missing words please help me
    14·2 answers
  • What is conclusive evidence that mixing sugar in water is a physical change
    14·1 answer
  • How to convert n butylbenzene to benzoic acid​
    15·1 answer
  • According to the Law of Conservation of Mass, how much water is produced if 22.5 g of
    15·1 answer
  • Hello how to draw the electron dot structure of H2S and F2?​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!