Answer:
correct option is (a)
The solution would be using this: C6H5COOH = H+ + C6H5COO Ka = 6.5 x 10^-5 = (H+)(C6H5COO-) over
(C6H5COOH)
Let X = moles per liter (H+) and also = moles per liter (C6H5COO-)
Ka = 6.5 x 10^-5 = (X)(X) over .350 molar = acid solution 6.5 x 10^-5 = X^2 over .350
X^2 = 6.5 x 10^-5 times .350 which = 2.275 x 10^-5
x = V2.275 x 10^-5
X = 1.5083 x 10^-5 moles per liter H+
pH = -log(H+) = -log 1.5083 x 10^-5 which
= 4.6215
Explanation:
Cholesterol concentration = 27 mg/ 232 mL
Change unit mg/ml to kg/m³
1 kg = 1000 g
1 g = 1000 mg
1 kg = 1000000 mg
1 kg = 10⁶ mg
10⁶ mg = 1 kg
1 mg = 10^-6 kg
m³ = 1000 L
1 L = 1000 mL
m³ = 1000000 mL
m³ = 10⁶ mL
10⁶ mL = m³
1 mL = 10^-6 m³
Cholesterol concentration = 27 mg/ 232 mL
27 × 10^-6 kg/ 232 × 10^-6 m³
= 27/232 kg/m³
Answer:
H3PO4 Mol mass..
= (3 x H1 = 3) + (1 x P31 = 31) + (4 x O16 = 64). = 98g/mol.
a)..Hydrogen: = 3 / 98 = 0.0306 x 100% = 3.06%.
b)..Phosphorus = 31/98 = 0.3162 x 100% = 31.63%.
c)..Oxygen = 64/98 = 0.6531 x 100% = 65.31%.
(Total = 100% H3PO4).
Explanation:
Find the molar mass of all the elements in the compound in grams per mole.
Find the molecular mass of the entire compound.
Divide the component's molar mass by the entire molecular mass.
You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.
Answer:
The 3rd option is correct
Explanation:
The element in group 13 and period 3 is aluminium which has the electron configuration
or [Ne] 3s^2 3p^1
