A horizontal 810-N merry-go-round of radius 1.40 m is started from rest by a constant horizontal force of 55 N applied tangentia
1 answer:
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The thing to do here is to balance the eqns that is to balance the stoichometric ratios or coefficients of the cpds.
hope you understand. all the best.
Answer:
The ball experiences the greater momentum change
Explanation:
The momentum change of each object is given by:
where
m is the mass of the object
v is the final velocity
u is the initial velocity
Both objects have same mass m and same initial velocity u. So we have:
- For the ball, the final velocity is
Since it bounces back (so, opposite direction --> negative sign) with same speed (so, the magnitude of the final velocity is still u). So the change in momentum is
- For the clay, the final velocity is
since it sticks to the wall. So, the change in momentum is
So we see that the greater momentum change (in magnitude) is experienced by the ball.
Answer:
The number of turns in the secondary coil is 4145 turns
Explanation:
Given;
the induced emf on the primary coil, = 95 V
the induced emf on the secondary coil, = 875 V
the number of turns in the primary coil, = 450 turns
the number of turns in the secondary coil, = ?
The number of turns in the secondary coil is calculated as;
Therefore, the number of turns in the secondary coil is 4145 turns.