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Greeley [361]
3 years ago
13

To receive AM radio, you want an RLC circuit that can be made to resonate at any frequency between 500 and 1650 kHz. This is acc

omplished with a fixed 3.83 µH inductor connected to a variable capacitor. What range of capacitance (in nF) is needed? smallest value in nF and largest value in nF
Physics
2 answers:
levacccp [35]3 years ago
6 0

The formula for resonant frequency is:

f_0=\frac{1}{2\pi\sqrt{LC} }

Given information:

f_{0\text{,small}}=500 \text{ kHz}\\f_{0\text{,large}}=1650 \text{ kHz}\\L=3.83\text{ } \mu \text{H}

Plug in the given values to find one value of capacitance:

500 \text{ kHz}=\frac{1}{2\pi\sqrt{C(3.83\text{ } \mu \text{H})} }\\C=2.645*10^{-8} \text{ F}=26.45 \text{ nF}

Plug in the given values to find the other value of capacitance:

1650 \text{ kHz}=\frac{1}{2\pi\sqrt{C(3.83\text{ } \mu \text{H})} }\\C=2.429*10^{-8} \text{ F}=2.429 \text{ nF}

This gives a range of 2.429 nF to 26.45 nF.

With significant figures taken into account, the range of capacitance is 2.43 nF to 30 nF.

joja [24]3 years ago
3 0

Answer:

The formula for resonant frequency is:

Explanation:

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We are told the mass of the ball is m=0.0555\ kg, the height above the spring where the ball is dropped is h=0.536\ m,  the length the ball compresses the spring is d=0.04897\ m and the acceleration of gravity is 9.8\ \frac{m}{s^{2}} .

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If we manipulate the equation we have that:

                                                    k=\frac{2mgh}{d^{2} }

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                                              k=\frac{0.58306\ \frac{kgm^{2}}{s^{2}}}{2.398x10^{-3}m^{2}}

                                                     k=243\ \frac{N}{m}

                                                   

                             

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bye

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bye

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