It is the acceleration of an object in free fall
Explanation:
When an object is in free fall, it is subjected only to one force: the force of gravity, which pulls the object downward, with a magnitude (near the Earth's surface) which is given by
where
m is the mass of the object
is the acceleration due to gravity
We can apply Newton's second law to the object in free fall:
where
F is the net force on the object
a is the acceleration of the object
m is the mass
However, since there is only the force of gravity acting on the object, the net force is equal to the force of gravity: so we can equate the two equations, obtaining that
Which means that the acceleration of an object in free fall (acted upon the force of gravity only) is equal to the acceleration due to gravity, .
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Answer:
A_resulting = 0.2 m
Explanation:
Let's analyze the impact of the pulse with the pole, this is a fixed obstacle that does not move therefore by the law of action and reluctant, the force that the pole applies on the rope is of equal magnitude to the force of the rope on the pole (pulse), but opposite directional, so the reflected pulse reverses its direction and sense.
With this information we analyze a point on the string where the incident pulse is and each reflected with an amplitude A = 0.1 m, the resulting is
A_res = 2A
A_resultant = 2 .01
A_resulting = 0.2 m
If by chance you mean any wave, the wave with the shortest wavelength/highest frequency is gamma rays.
Answer:
A
Explanation:
traveling north no displacement ,west displacement is 10,
Answer:
(a) 2.45×10⁵ N/m
(b) 0.204 m
Explanation:
Here we have that to have a velocity of 2.25 m/s then the relationship between the elastic potential energy of the spring and the kinetic energy of the rocket must be
Elastic potential energy of the spring = Kinetic energy of the rocket
Where:
k = Force constant of the spring
x = Extension of the spring
m = Mass of the rocket
v = Velocity of the rocket
Therefore,
or
(b) Since the maximum acceleration is given as 5.00×g we have
Maximum acceleration = 5.00 × 9.81 = 49.05 m/s²
Hence the force on the rocket is then;
Force = m×a = 1020 × 49.05 = 50,031 N
Therefore,
(a) From which
or
Force constant of the spring, k = 2.45×10⁵ N/m.
