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3 years ago

How many molecules are in a 189 g sample of carbon tetrabromide, CBr4?

Chemistry

2 answers:

Svet_ta [14]3 years ago

4 0

Answer:

3.4321229*10^23 molecules.

Explanation:

1 mole of CBr4 contains 6.0221409*10^23 molecules (Avogadro's Number).

The molar mass of this compound is 12.011 + 4(79.904)

= 331.627 g.

So the answer is (189/ 331.627) * 6.0221409*10^23

= 3.4321229*10^23 molecules.

svetoff [14.1K]3 years ago

3 0

Answer:

.57 moles

Explanation:

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