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strojnjashka [21]

2 years ago

8

A wire with a resistance R is lengthened to 3.07 times its original length by pulling it through a small hole. Find the new resi

stance of the wire after it was stretched.

1 answer:

charle [14.2K]2 years ago

4 0

Explanation:

Below is an attachment containing the solution.

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What are the three types of motion

Cloud [144]

Rectilinear Motion, Circular Motion and Periodic Motion.

7 0

2 years ago

Two students walk in the same direction along a straight path, at a constant speed one at 0.90 m/s and the other at 1.90 m/s. a.

creativ13 [48]

Answer: a) 456.66 s ; b) 564.3 m

Explanation: The time spend to cover any distance a constant velocity is given by:

v= distance/time so t=distance/v

The slower student time is: t=780m/0.9 m/s= 866.66 s

For the faster students t=780 m/1,9 m/s= 410.52 s

Therefore the time difference is 866.66-410.52= 456.14 s

In order to calculate the distance that faster student should walk

to arrive 5,5 m before that slower student, we consider the follow expressions:

distance =vslower*time1

distance= vfaster*time 2

The time difference is 5.5 m that is equal to 330 s

replacing in the above expression we have

time 1= 627 s

time2 = 297 s

The distance traveled is 564,3 m

8 0

3 years ago

In 1898, the world land speed record was set by Gaston Chasseloup-Laubat driving a car named Jeantaud. His speed was 39.24 mph (

FromTheMoon [43]

Answer:

the acceleration $a^{\to} = (0.0159 \ \ m/s^2 )i$

Explanation:

Given that:

the initial speed v₁ = 0 m/s i.e starting from rest ; since the car accelerates at a distance Δx = 6 miles in order to teach that final speed v₂ of 63.15 km/h.

So; the acceleration for the first 6 miles can be calculated by using the formula:

v₂² = v₁² + 2a (Δx)

Making acceleration a the subject of the formula in the above expression ; we have:

v₂² - v₁² = 2a (Δx)

$a = \dfrac{v_2^2 - v_1^2 }{2 \Delta x}$

$a = \dfrac{(63.15 \ km/s)^2 - (0 \ m/s)^2 }{2 (6 \ miles)}$

$a = \dfrac{(17.54 \ m/s)^2 - (0 \ m/s)^2 }{2 (9.65*10^3 \ m)}$

$a =0.0159 \ m/s^2$

Thus;

Assume the car moves in the +x direction;

the acceleration $a^{\to} = (0.0159 \ \ m/s^2 )i$

7 0

2 years ago

A net force of 100 n is moving a mass with an acceleration of 5 m/s2. what is the mass of the object? 0.05 kg 20 kg 95 kg 500 kg

dezoksy [38]

F = ma
100n = m(5m/s^2)
100/5 = 20

6 0

3 years ago

Read 2 more answers

A neutral atom of uranium (U) has 146 neutrons and a mass number of 238. How many protons does it have?

BARSIC [14]

Answer:

92 protons

Explanation:

The mass number is 238 , so the nucleus has <u>238 particles</u> in total, including <u>146 neutrons</u>. So to calculate the number of neutrons we have to subtract: 238 − 146 = 92

4 0

2 years ago

Read 2 more answers