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ziro4ka [17]
2 years ago
11

A bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of 5.70 x 10^5 m/s^2 for 9.

60 x 10^−4 s. What is its muzzle velocity (in m/s) (that is, its final velocity)? (Enter the magnitude.)
Physics
1 answer:
s2008m [1.1K]2 years ago
3 0

Answer:

Final speed, v = 547.2 m/s

Explanation:

Initial velocity of the bullet, u = 0

Acceleration of the bullet, a=5.7\times 10^5\ m/s^2

Time taken, t=9.6\times 10^{-4}\ s

Let v is the final velocity of the muzzle. It can be calculated using the first equation of motion as :

v=u+at

v=at      

v=5.7\times 10^5\ m/s^2\times 9.6\times 10^{-4}\ s    

v = 547.2 m/s

So, the final speed of the muzzle is 547.2 m/s. Hence, this is the required solution.                                

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Answer:

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b)

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9 x 10⁹ [ 20 x 10⁻⁹ / .05 + - 20 x 10⁻⁹ / .05 + 10 x 10⁻⁹ / .03 ]

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