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malfutka [58]
3 years ago
8

13. Marissa buys a prepaid cell phone card for $25. The charge for a phone call is $0.13 per minute, or part of a minute. Write

and solve an inequality to determine the greatest number of minutes that Marissa can talk. Which is the correct way to interpret your solution? * (1 Point) Marissa can talk for no less than 192 minutes, Marissa can talk for at most 192 minutes, Marissa can talk for fewer than 192 minutes, Marissa can talk above 192 minutes.​
Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

The correct option is;

Marissa can talk for at most 192 minutes

Step-by-step explanation:

The amount for which Marissa buys the prepaid cell phone card = $25

The charge for a phone call using the recharge card = $0.13 per minute

The greatest number of minutes Marissa can call is given by the the following inequality;

t < $25/($0.13/minute)

$25/($0.13/minute) = (192 + 4/13) minutes

Therefore;

t <  (192 + 4/13) minutes

The cost of 192 minutes = 192 minutes × $0.13 per minute = $24.96

The amount of credit left on the $25 recharge = $25 - $24.96 = $0.04

The minimum  charge for calls = $0.13

The amount remaining after 192 minutes $0.04 is less than the amount to make a call $0.13

Therefore;

t ≤ 192 minutes

Therefore, Marissa can talk for at most 192 minutes.

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A bacteria culture starts with 12,000 bacteria and the number doubles every 50 minutes.
Vlada [557]

Answer:

a)  y=12000(2)^{\frac{t}{50}}

b)  Approx. 27,569 bacteria

c)  About 103 minutes

Step-by-step explanation:

a)

This will follow exponential modelling with form of equation shown below:

y=Ab^{\frac{t}{n}}

Where

A is the initial amount (here, 12000)

b is the growth factor (double, so growth factor is "2")

n is the number of minutes in which it doubles, so n = 50

Substituting, we get our formula:

y=Ab^{\frac{t}{n}}\\y=12000(2)^{\frac{t}{50}}

b)

To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.

Remember, t is in minutes, so

1 hour = 60 minutes

t = 60

Substituting, we get:

y=12000(2)^{\frac{t}{50}}\\y=12000(2)^{\frac{60}{50}}\\y=12000(2)^{\frac{6}{5}}\\y=27,568.76

The number of bacteria after 1 hour would approximate be <u>27,569 bacteria</u>

<u></u>

c)

To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

y=12000(2)^{\frac{t}{50}}\\50,000=12,000(2)^{\frac{t}{50}}\\4.17=2^{\frac{t}{50}}\\Ln(4.17)=Ln(2^{\frac{t}{50}})\\Ln(4.17)=\frac{t}{50}*Ln(2)\\\frac{t}{50}=\frac{Ln(4.17)}{Ln(2)}\\\frac{t}{50}=2.06\\t=103

After about 103 minutes, there will be 50,000 bacteria

4 0
3 years ago
Answer and please show the work !
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Step-by-step explanation:

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Substitute the numbers for the variables.

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