Answer: The first.
Step-by-step explanation: If you draw out a triangle and lable the points on each point with values from each triangle, you get J=M, K=N, and L=O. The first is the only one that proves it.
Answer:
prob more time ngl
Step-by-step explanation:
Answer:
y = 2/3x +6 for x< -3
y = 2/3x +1 for x> 3
Step-by-step explanation:
The graph is a line for x < -3
( - 6,2) and ( -3,4)
The slope is m= ( y2-y1)/(x2-x1)
m = ( 4-2)/(-3 - -6) = 2/ ( -3+6) = 2/3
The slope is 2/3
Using point slope form
y-y1 = m(x-x1) and the point ( -6,2)
y -2 = 2/3(x - -6)
y -2 = 2/3(x +6)
y-2 = 2/3 x +4
y = 2/3x +6 x< -3
The graph is a line for x > 3
(3,3) and ( 6,5)
The slope is m= ( y2-y1)/(x2-x1)
m = ( 5-3)/(6-3) = 2/ (3) = 2/3
The slope is 2/3
Using point slope form
y-y1 = m(x-x1) and the point (6,5)
y -5 = 2/3(x - 6)
y-5 = 2/3 x -4
y = 2/3x +1 x> 3
If the polygons are similar then the sides are in proportion.
![\dfrac{32}{24}=\dfrac{32:8}{24:8}=\dfrac{4}{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B32%7D%7B24%7D%3D%5Cdfrac%7B32%3A8%7D%7B24%3A8%7D%3D%5Cdfrac%7B4%7D%7B3%7D)
Therefore we have the equations:
![\dfrac{x-1}{6}=\dfrac{4}{3}\qquad\text{cross multiply}\\\\3(x-1)=(4)(6)\\\\3x-3=24\qquad\text{add 3 to both sides}\\\\3x=27\qquad\text{divide both sides by 3}\\\\\boxed{x=9}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx-1%7D%7B6%7D%3D%5Cdfrac%7B4%7D%7B3%7D%5Cqquad%5Ctext%7Bcross%20multiply%7D%5C%5C%5C%5C3%28x-1%29%3D%284%29%286%29%5C%5C%5C%5C3x-3%3D24%5Cqquad%5Ctext%7Badd%203%20to%20both%20sides%7D%5C%5C%5C%5C3x%3D27%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%203%7D%5C%5C%5C%5C%5Cboxed%7Bx%3D9%7D)
![\dfrac{y+1}{21}=\dfrac{4}{3}\qquad\text{cross multiply}\\\\3(y+1)=(21)(4)\\\\3y+3=84\qquad\text{subtract 3 from both sides}\\\\3y=81\qquad\text{divide both sides by 3}\\\\\boxed{y=27}](https://tex.z-dn.net/?f=%5Cdfrac%7By%2B1%7D%7B21%7D%3D%5Cdfrac%7B4%7D%7B3%7D%5Cqquad%5Ctext%7Bcross%20multiply%7D%5C%5C%5C%5C3%28y%2B1%29%3D%2821%29%284%29%5C%5C%5C%5C3y%2B3%3D84%5Cqquad%5Ctext%7Bsubtract%203%20from%20both%20sides%7D%5C%5C%5C%5C3y%3D81%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%203%7D%5C%5C%5C%5C%5Cboxed%7By%3D27%7D)