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Naya [18.7K]
3 years ago
11

The law of conservation of momentum states that the total momentum of interacting objects does not _______. This means the total

momentum _____ a collision or explosion is equal to the to momentum ______ a collision or explosion.
Fill in the blanks.
Physics
2 answers:
Nata [24]3 years ago
5 0

Explanation:

Law of conservation of momentum states that in an isolated system when two objects collide with each other then total momentum before and after the collision is equal.

Thus, we can conclude that the law of conservation of momentum states that the total momentum of interacting objects does not change. This means the total momentum before a collision or explosion is equal to the to momentum after a collision or explosion.

Nezavi [6.7K]3 years ago
4 0

Answer: The correct answers are not change, before and after.

Explanation:

Law of conservation of momentum states that in an isolated system, the total momentum remains conserved. This means that the total momentum before collision is equal to the total momentum after collision remains same.

The law of conservation of momentum is conserved because no external force is acting.

Therefore, The law of conservation of momentum states that the total momentum of interacting objects does not change. This means the total momentum before collision or explosion is equal to the momentum after a collision or explosion.

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A gold nucleus (with a radius of 6.5 fm in its rest system, containing 197 protons and neutrons of rest mass 939 MeV/c2 each) is
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Answer:

1.9982154567\times 10^{-18}\ kgm/s

762474.685899 MeV

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Explanation:

v = 0.97 c

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Relativistic momentum is given by

p=\dfrac{m_0v}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow p=\dfrac{939\times 10^6\times 1.6\times 10^{-19}\times 0.97\times 3\times 10^8}{\sqrt{1-\dfrac{0.97^2c^2}{c^2}}}\\\Rightarrow p=\dfrac{(939\times 10^6\times 1.6\times 10^{-19})J/c^2\times 0.97c}{\sqrt{1-0.97^2}}\\\Rightarrow p=\dfrac{(939\times 10^6\times 1.6\times 10^{-19})\times 0.97}{c\sqrt{1-0.97^2}}\\\Rightarrow p=\dfrac{(939\times 10^6\times 1.6\times 10^{-19})\times 0.97}{3\times 10^8\times \sqrt{1-0.97^2}}\\\Rightarrow p=1.9982154567\times 10^{-18}\ kgm/s

The momentum is 1.9982154567\times 10^{-18}\ kgm/s

Energy in MeV

E=\dfrac{m_0c^2}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow E=\dfrac{939}{\sqrt{1-0.97^2}}\\\Rightarrow E=3862.52987766\ MeV

Total energy is

E'=3862.52987766+7.9=3870.42987766\ MeV

The total energy is 3870.42987766 MeV

For all the nucleons

E_t=197\times 3870.42987766=762474.685899\ MeV

The energy is 762474.685899 MeV

Diameter = 2\times 6.5=13\ fm

From length contraction

D'=D\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow D'=13\sqrt{1-0.97^2}\\\Rightarrow D'=3.1603639031\ fm

The diameter would be 3.1603639031 fm

3 0
3 years ago
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