A = 59.35cm
B = 196.56g
C = 74.65g
<u>Explanation:</u>
We know,

and L = x+y
1.
Total length, L = 100cm
Weight of Beam, W = 71.8g
Center of mass, x = 49.2cm
Added weight, F = 240g
Position weight placed from fulcrum, y = ?

Therefore, position weight placed from fulcrum is 59.35cm
2.
Total length, L = 100cm
Center of mass, x = 47.8 cm
Added weight, F = 180g
Position weight placed from fulcrum, y = 12.4cm
Weight of Beam, W = ?

Therefore, weight of the beam is 196.56g
3.
Total length, L = 100cm
Center of mass, x = 50.8 cm
Position weight placed from fulcrum, y = 9.8cm
Weight of Beam, W = 72.3g
Added weight, F = ?

Therefore, Added weight F is 74.65g
A = 59.35cm
B = 196.56g
C = 74.65g
B is the correct answer because an object moving ten north m/s will turn into 15m/s which as you can tell is accelerating.
Vai c fude
..........................................................................
Answer:
d ............................
M = 2.2 g = 2.2 x 10⁻³ kg, the mass of the bug.
r = 3.0 cm = 0.03 m, the radial distance from the center.
The angular speed is
ω = 280 rpm
= (280 rev/min)*(2π rad/rev)*(1/60 min/s)
= 29.3215 rad/s
The moment of inertia of the bug is
I = mr²
= (2.2 x 10⁻³ kg)*(0.03 m)²
= 1.98 x 10⁻⁶ kg-m²
Calculate the angular momentum of the bug.
J = Iω
= (1.98 x 10⁻⁶ kg-m²)*(29.3215 rad/s)
= 5.806 x 10⁻⁵ (kg-m²)/s
Answer: 5.806 x 10⁻⁵ (kg-m²)/s