Answer:
an absorber of x-ray
Explanation:
To make x-ray detection/vision work, you will need at least two items: a source of x-ray and absorbed or x-ray.
The object you want to see itself doesn't have to be the source, but it has to absorb some of the rays instead. When doing a chest x-ray test, the medical employee will put your chest between absorber and source. The heart can absorb some of the rays so it will appear more white than lungs who made of air and won't absorb the rays.
Boyle's law and Charles's law tells us that the volume of a gas is dependent on pressure and temperature. That is why scientists have to also take measurements of the pressure and temperature when they take the measurement for volume of the gas.
Answer: Yes.
Explanation:
Oxygen has a bond order of two. The bond order of Oxygen molecule is calculated, where the [<em>eight valence electrons in bonding molecular orbitals</em> minus (-) <em>four valence electrons in antibonding molecular orbitals</em>]/2 in the electron configuration.
Atoms/molecules where electrons are paired are diamagnetic (repelled by both poles of a magnetic); while atoms/molecules that have one or more unpaired electrons are paramagnetic (attracted to magnetic field).
The two unpaired electrons of dioxygen molecules has made it <u>paramagnetic</u>. By pouring liquid oxygen between the poles of a strong magnet, the liquid stream will be contained by the filed and fills up the space between the poles.
Answer:
P₂ = 392720.38 Pa = 392.72 kPa
Explanation:
Given
D₁ = 5 cm = 0.05 m
D₂ = 10 cm = 0.10 m
v₁ = 8 m/s
P₁ = 380 kPa = 380000 Pa
α = 1.06
ρ = 1000 kg/m³
g = 9.8 m/s²
We can use the following formula
(P₁ / (ρg)) + α*(V₁² / (2g)) + z₁ = (P₂ / (ρg)) + α*(V₂² / (2g)) + z₂ + +hL
knowing that z₁ = z₂ we have
(P₁ / (ρg)) + α*(V₁² / (2g)) = (P₂ / (ρg)) + α*(V₂² / (2g)) + +hL <em> (I)
</em>
Where
V₂ can be obtained as follows
V₁*A₁ = V₂*A₂ ⇒ V₁*( π* D₁² / 4) = V₂*( π* D₂² / 4)
⇒ V₂ = V₁*(D₁² / D₂²) = (8 m/s)* ((0.05 m)² / (0.10 m)²)
⇒ V₂ = 2 m/s
and
hL is a head loss factor: hL = α*(1 - (D₁² / D₂²))²*v₁² / (2*g)
⇒ hL = (1.06)*(1 – ((0.05 m) ² / (0.10 m)²))²*(8 m/s)² / (2*9.8 m/s²)
⇒ hL = 1.9469 m
Finally we get P₂ using the equation <em>(I)
</em>
⇒ P₂ = P₁ - ((V₂² - V₁²)* α*ρ / 2) – (ρ*g* hL)
⇒ P₂ = 380000 Pa - (((2 m/s)² - (8 m/s)²)*(1.06)*(1000 kg/m³) / 2) – (1000 kg/m³*9.8 m/s²*1.9469 m)
⇒ P₂ = 392720.38 Pa = 392.72 kPa
Answer:
The speed of the piñata immediately after being cracked by the stick is .
Explanation:
Using the conservation of linear momentum:
(1)
Here:
m(s) is the mass of the stick
m(p) is the mass of the piñata
v(is) is the initial velocity of the stick
v(fp) is the final velocity of the piñata
So, we just need to solve the equation (1) to v(fp).
I hope it helps you!