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ozzi
3 years ago
14

Which statement does NOT describe redesign?

Physics
1 answer:
pantera1 [17]3 years ago
4 0
D. It happens all the time
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In a polytropic process, with the exponent n = k, where k is the specific heat ratio, 1.0 kg of neon (an ideal gas) in a frictio
Elden [556K]
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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3 0
3 years ago
2. Using examples to describe each term, differentiate
melisa1 [442]

Answer: find the answer in the explanation

Explanation:

Average velocity is the average value of magnitude of initial velocity and final velocity.

If U = initial velocity and V = final velocity, then average velocity can be expressed as

Average velocity = ( U + V )/2

A vehicle who takes 60 minutes to cover 30 miles north and then 30 miles south and end up at the same place, has an average speed of 60 miles divided by 60 minutes, or 1 mile per minute.

Instantaneous velocity is the distance covered in a specific direction per time taken. Instantaneous velocity can be expressed as

Velocity = displacement/ time.

Uniform velocity occurs when we have a constant velocity. That is, when velocity does not change. When a vehicle travels in equal distances in equal intervals of time.

7 0
3 years ago
The two forces of a 3rd law pair always act on different bodies. The two forces of a 3rd law pair always act on different bodies
svetoff [14.1K]

1. The two forces of a 3rd law pair always act on different bodies.

TRUE

SO above statement is TRUE because Newton's III law is valid for two different objects where one object will exert force and other body will exert reaction force on it.

2. Part F Given that two bodies interact via some force, the accelerations of these two bodies have the same magnitude but opposite directions. (Assume no other forces act on either body.)

FALSE

This is false because the force of action and Reaction is same on two different objects but for finding acceleration we need to divide the force by mass of two objects and since the mass of two bodies may be different so we can say that acceleration may be different.

3. Part G According to Newton's 3rd law, the force on the (smaller) moon due to the (larger) earth is

(i) greater in magnitude and antiparallel to the force on the earth due to the moon.

(ii) greater in magnitude and parallel to the force on the earth due to the moon.

(iii) equal in magnitude but antiparallel to the force on the earth due to the moon.

(iv) equal in magnitude and parallel to the force on the earth due to the moon.

(v) smaller in magnitude and antiparallel to the force on the earth due to the moon.

(vi) smaller in magnitude and parallel to the force on the earth due to the moon.

Since Earth and moon is an isolated system so here Newton's III law is valid due to which we can say that two forces are equal in magnitude but opposite in sign

so correct answer will be

equal in magnitude but antiparallel to the force on the earth due to the moon.

4 0
3 years ago
Find the heat given off if 1 kg of 125 degree C steam is cooled to 50 degree C water.
Gnom [1K]
  • T_i=125°C=398K
  • T_f=50°C=323K
  • c=4184J/kg°K
  • m=1kg
  • ∆T=T_f-T_i=398-323=75K

\\ \sf{:}\Rrightarrow Q=mc\Delta T

\\ \sf{:}\Rrightarrow Q=1(4184)(75)

\\ \sf{:}\Rrightarrow Q=313800J

\\ \sf{:}\Rrightarrow Q=313.8KJ

4 0
3 years ago
4. There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400 nm. It is not
vampirchik [111]

The ranges of frequency are:

UVA: [7.50-9.38]\cdot 10^{14} Hz

UVB: [9.38-10.71]\cdot 10^{14} Hz

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is the following:

f = \frac{c}{\lambda}

where

f is the frequency

c=3.0\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

For the UVA, the range of wavelength is 320 nm - 400 nm, so

\lambda_1 = 320 \cdot 10^{-9} m\\\lambda_2 = 400 \cdot 10^{-9} m

So the corresponding frequencies are

f_1 = \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz\\f_2= \frac{3\cdot 10^8}{400\cdot 10^{-9}}=7.50\cdot 10^{14} Hz

For the UVB, the range of wavelength is 280 nm - 320 nm, so

\lambda_1 = 280 \cdot 10^{-9} m\\\lambda_2 = 320 \cdot 10^{-9} m

So the corresponding frequencies are

f_1 = \frac{3\cdot 10^8}{280\cdot 10^{-9}}=1.07\cdot 10^{15} Hz\\f_2= \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz

So the ranges of frequency are:

UVA: [7.50-9.38]\cdot 10^{14} Hz

UVB: [9.38-10.71]\cdot 10^{14} Hz

Learn more about waves, frequency and wavelength:

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brainly.com/question/9077368

#LearnwithBrainly

3 0
3 years ago
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