Question

A bicycle generator rotates at 154 rads/s, producing an 16.5 V peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.68 T field. How many turns are in the coil?

Answer 1

Answer:

525.2

Explanation:

w = 154 rad/s, e0 = 16.5 V, A = 1 x 3 = 3 cm^2 = 3 x 10^-4 m^2, B = 0.68 T

Let the number of turns be N.

By use of law of electromagnetic induction

e0 = N B A w

16.5 = N x 0.68 x 3 x 10^-4 x 154

N = 525.2

Answer 2

Answer:

N = 525 Turns

Explanation:

Peak Voltage of a coil is given by the formula

$V_{peak} = NBA\omega$

here we know that

$V_{peak} = 16.5 Volts$

B = 0.68 T

$\omega = 154 rad/s$

$Area = (0.01 m)\times (0.03 m)$

$Area = 3 \times 10^{-4} m^2$

now we have

$16.5 = N(0.68)(3 \times 10^{-4})(154)$

$N = 525$