The solution for this problem is computed by through this formula, F = kQq / d²Plugging in the given values above, we can now compute for the answer.
F = 8.98755e9N·m²/C² * -(7e-6C)² / (0.03m)² = -489N, the negative sign denotes attraction.
Answer:
45000 K .
Explanation:
Given :
A liter of a gas weigh 2 gram at 300 kelvin temperature and 1 atm pressure
We need to find the temperature in which 1 litre of the same gas weigh 1 gram
in pressure 75 atm.
We know, by ideal gas equation :

Here , n is no of moles , 
Putting initial and final values and dividing them :


Hence , this is the required solution.
Answer:
BELOW
Explanation:
Seattle (near water) would have hotter temperatures because it is by a large body of water. Unlike Bismarck which is surrounded by land. Bismarck would get hotter. Seattle would be affected the large body of water which heats more slowly than the continent warming.
The answer would probably be B.