Answer:
really?!
Explanation:
this is a test your suppose to answer it
The wax heats up and evaporates
Answer:
A) C₇H₆O₂
B) C₁₄H₁₂O₄
Explanation:
To determine the empirical and molecular formula of the compound, we need to follow a series of steps.
Step 1: Divide each percentage by the atomic mass of the element
C: 43.74/12.01 = 3.64
H: 3.14/1.01 = 3.11
O: 16.61/16.00 = 1.04
Step 2: Divide all the numbers by the smallest one, i.e. 1.04
C: 3.64/1.04 = 3.5
H: 3.11/1.04 = 3
O: 1.04/1.04 = 1
Step 3: Multiply all the numbers by 2, so that all of them are integers
C: 3.5 × 2 = 7
H: 3 × 2 = 6
O: 1 × 2 = 2
The empirical formula of the compound is C₇H₆O₂.
Step 4: Determine the molar mass of the empirical formula
M(C₇H₆O₂) = 7 × M(C) + 6 × M(H) + 2 × M(O)
M(C₇H₆O₂) = 7 × 12.01 g/mol + 6 × 1.01 g/mol + 2 × 16.00 g/mol = 122.13
Step 5: Calculate "n"
We will use the following expression
n = M(compound) / M(empirical formula)
n = (244.26 g/mol) / (122.13 g/mol) = 2
Step 6: Determine the molecular formula of the compound
We determine the molecular formula by multiplying the empirical formula by "n".
C₇H₆O₂ × 2 = C₁₄H₁₂O₄
Periodic table is a table of elements arranged in periods and groups in terms similar chemical and physical characteristics.The ion charge of an element depends on the number of electrons may loose or gain to form a stable ion. Elements in group iv have four electrons in the outermost energy level, therefore their ionic charge would be +4 or - 4 since they can gain or loose 4 electrons to form ions.
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