This problem is providing us with the mass equivalent to one troy ounce. Thus, the troy ounces of gold in one short ton of average Nevada ore is required and found to be the 0.103 otz according to the following dimensional analysis.
<h3>Dimensional analysis</h3>
In chemistry, a raft of problems do not always provide an equation in order to be solved yet dimensional analysis can be applied, so as to obtain the desired amount in the required units.
Thus, since this problem asks for try ounces in an average Nevada ore, which has 3.2 grams of gold per short ton of ore, one can solve the following setup in order to obtain the required answer in otz:
![\frac{3.2gAu}{1short-ton}*1short-ton*\frac{1otz}{31.1g} \\](https://tex.z-dn.net/?f=%5Cfrac%7B3.2gAu%7D%7B1short-ton%7D%2A1short-ton%2A%5Cfrac%7B1otz%7D%7B31.1g%7D%20%5C%5C)
Where the short tons are cancelled out as well as the grams, in order to obtain:
![0.103 otz](https://tex.z-dn.net/?f=0.103%20otz)
Learn more about dimensional analysis: brainly.com/question/10874167
Answer:
I'm guessing that the underlined word is barbarous ... if so the correct answer would be uncivilized.
Explanation:
Explanation:
Rate law is defined as the rate of a reaction is directly proportional to the concentration of reactants at constant temperature.
![Rate \propto [\text{concentration of reactant}]^{n}](https://tex.z-dn.net/?f=Rate%20%5Cpropto%20%5B%5Ctext%7Bconcentration%20of%20reactant%7D%5D%5E%7Bn%7D)
= k ![[\text{concentration of reactant}]^{n}](https://tex.z-dn.net/?f=%5B%5Ctext%7Bconcentration%20of%20reactant%7D%5D%5E%7Bn%7D)
where, k = rate constant
n = order of reaction
For the given reaction, ![2H_{2} + 2NO \rightarrow N_{2} + 2H_{2}O](https://tex.z-dn.net/?f=2H_%7B2%7D%20%2B%202NO%20%5Crightarrow%20N_%7B2%7D%20%2B%202H_%7B2%7DO)
Hence, its rate will be as follows.
Rate = ![k[H_{2}][NO]](https://tex.z-dn.net/?f=k%5BH_%7B2%7D%5D%5BNO%5D)
Also, it is known that slowest step in a chemical reaction is the rate determining step.
Hence, for the given rate law correct reaction is as follows.
Step 1 :
(slow)
Balancing this equation it becomes
(slow)
Step 2:
(fast)
First, we write the reaction equation for the formation of HCl from hydrogen and chlorine:
H₂ + Cl₂ → 2HCl
Now, we substitute the values of the enthalpies, denoting that of the Cl-Cl bond by x:
435 + x = -92 + 2(431)
x = 335
The bond dissociation enthalpy for the Cl-Cl bond is 335 kJ/mol
The correct answer is 0.72 g/cm3
Explanation:
The density of a material depends on both its mass (amount of matter), which is usually provided in grams (g), and its volume (space occupied), which is provided in units such as cubic centimeters cm3. Moreover, to find how dense the material is, take the mass and divide it into the volume. The process for finding the density of the block of wood is shown below:
![d = \frac{m}{v}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7Bm%7D%7Bv%7D)
![d = \frac{46 g}{64 cm3}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B46%20g%7D%7B64%20cm3%7D)
![d = 0.718 g/cm3](https://tex.z-dn.net/?f=d%20%3D%200.718%20g%2Fcm3)
This means the density is 0.71g/cm3 and this can be rounded to 0.72 g/cm3