C. Tetraphosphorus trisulfide
Answer:
Chemical properties can be recognized only when substances react or do not react chemically with one another, that is, when they undergo a change in composition. A chemical property of one substance usually involves its ability to react or not react with another specific substance.
Answer:
84.2 grams
Explanation:
you have to multiply 8.42x10^18 to get the answer above
Answer:
The answer to your question is 0.10 M
Explanation:
Data
Molarity = ?
mass of Sucrose = 125 g
volume = 3.5 l
Formula
Molarity = moles / volume
Process
1.- Calculate the molar mass of sucrose
C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)
= 144 + 22 + 176
= 342 g
2.- Convert the mass of sucrose to moles
342 g of sucrose ------------------- 1 mol
125 g of sucrose -------------------- x
x = (125 x 1) / 342
x = 0.365 moles
3.- Calculate the molarity
Molarity = 0.365 / 3.5
4.- Result
Molarity = 0.10
Answer:
0!
Explanation:
- You need to search your pKa values for Asn (2.14, 8.75), Gly (2.35, 9.78) and Leu(2.33, 9.74), the first value corresponding to -COOH, the second to -NH3 (a third value would correspond to an R group, but in this case that does not apply), and we'll build a table to find the charges for your possible dissociated groups at indicated pH (7), we need to remember that having a pKa lower than the pH will give us a negative charge, having a pKa bigger than pH will give us a positive charge:
-COOH -NH3
pH 7------------------------------------------------------
Asn - +
Gly - +
Leu - +
- Now that we have our table we'll sketch our peptide's structure:
<em>HN-Asn-Gly-Leu-COOH</em>
This will allow us to see what groups will be free to react to the pH's value, and which groups are not reacting to pH because are forming the bond between amino acids. In this particular example only -NH group in Ans and -COOH in Leu are exposed to pH, we'll look for these charges in the table and add them to find the net charge:
+1 (HN-Asn)
-1 (Leu-COOH)
=0
The net charge is 0!
I hope you find this information useful and interesting! Good luck!
