A 1,492.3-kg airplane travels down the runway. Each of its four engines provides a force of

Physics

1 answer:

Fittoniya [83]3 years ago

3 0

The acceleration of the air plane is $3.879 \mathrm{m} / \mathrm{s}^{2}$

<u>Explanation:</u>

Given:

The mass of the air plane = 1492.3 kg

Force of each four engine = 1447.5 N

So, the total force of four engines can be calculated as = 4(1447.5) = 5790 N

The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

$\text {Force }(F)=m \times \text { acceleration }(a)$

The above equation can be written as below to find acceleration,

$a=\frac{F}{m}$

Now. Substitute the given values, we get,

$a=\frac{5790}{1492.3}=3.879 \mathrm{m} / \mathrm{s}^{2}$

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Explanation:

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