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Alex777 [14]
3 years ago
4

density describes how much mass is contained in a certain volume. knowing how far apart molecules are in each state, which best

ranks solids, liquids, and gasses from least dense to most dense?
Chemistry
2 answers:
vladimir2022 [97]3 years ago
7 0

Answer: The order will be: gases < liquids < solids

Explanation:

Density is defined as measure of mass of substance present in unit volume of the substance.It is measured in gram per centimeter cube g/cm^3.

Density=\frac{Mass}{Volume}

In solid state, molecules are strongly associated with each other that is they are tightly packed. Due to this tight packing, more mass will be present in a unit volume.

In liquid state, molecules are weakly associated with each other. Due to this weak association, the mass present in a unit volume will be less than that of the solid state.

In gaseous state, molecules are very far apart from each other. Due to this very weak association, the mass present in a unit volume will be less than that of the solid and the liquid state

So,the order from least dense to most dense will be:

Gases < liquids < solids

spayn [35]3 years ago
7 0

Answer:

on edge its A)Gasses are denser than liquids.  

Explanation:

Good day MERICA YEE YEE

You might be interested in
A 19.0 L helium tank is pressurized to 26.0 atm. When connected to this tank, a balloon will inflate because the pressure inside
vesna_86 [32]

Answer:

The new volume of the balloon when the pressure equalised with the pressure of the atmosphere = 494 L.

The balloon expands by am additional 475 L.

Explanation:

Assuming Helium behaves like an ideal gas and temperature is constant.

According to Boyle's law for ideal gases, at constant temperature,

P₁V₁ = P₂V₂

P₁ = 26 atm

V₁ = 19.0 L

P₂ = 1 atm (the balloon is said to expand till the pressure matches the pressure of the atmpsphere; and the pressure of the atmosphere is 1 atm)

V₂ = ?

P₁V₁ = P₂V₂

(26 × 19) = 1 × V₂

V₂ = 494 L (it is assumed the balloon never bursts)

The new volume of the balloon when the pressure equalised with the pressure of the atmosphere = 494 L.

The balloon expands by am additional 475 L.

Hope this Helps!!!

6 0
4 years ago
Which of the following would be expected to dissolve readily in the nonpolar solvent CCl4?
ratelena [41]

<em>The given answer would dissolve readily in the nonpolar solvent CCl4;</em>

D. Grease

<u>Because water molecules are polar, they interact with the sodium and chloride ions. In general, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes. </u>

3 0
4 years ago
3.364 g of hydrated barium chloride of BaCL2.xH2O was dissolved in water and made up to a total volume of 250.0 mL. 10.00 mL of
atroni [7]

<u>Given:</u>

Mass of hydrated barium chloride = 3.364 g

Total volume of barium chloride V(total)= 250 ml

Volume taken for titration V = 10 ml

Volume of AgNO3 consumed = 46.92 ml

Concentration of AgNO3 = 0.0253 M

<u>To determine:</u>

The value of x i.e. the water of hydration in BaCl2

<u>Explanation:</u>

The net ionic equation is-

Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

Based on the reaction stoichiometry: Equal moles of Ag+ and Cl- combine to form AgCl

Moles of Ag+ consumed = moles of Cl- present

Moles of Ag+ = V(AgNO3) * M(AgNO3) = 0.04692 * 0.0253 = 0.00119moles

Moles of Cl- present = 0.00119 moles

Thus, 0.00119 moles of Cl- are present in 10 ml of the solution

Therefore, number of moles of Cl- in 250 ml would be-

= 0.00119 * 250 /10 = 0.02975 moles of cl-

Now:

2 moles of Cl- are present in 1 mole of BaCl2

Therefore, 0.02975 moles of Cl- correspond to- 0.02975 * 1/2 = 0.01488 moles of BaCl2

Molar mass of BaCl2 = 208.22 g/mol

Thus, mass of BaCl2 = 0.01488 moles * 208.22 g.mol-1 = 3.098 g

Mass of water of hydration = 3.364 - 3.098 = 0.266 g

# moles of water 'x' = .266/18 = 0.015 ≅ 1

Ans: Formula for hydrated barium chloride = BaCl2. 1H2O



7 0
4 years ago
HELP ME PLEASE HELP
AURORKA [14]

Answer:

In homogeneous solute dissolves completely in latter it doesn't

homogeneous example: sugar and water

heterogeneous: oil and water

6 0
3 years ago
Determine the mass of grams of led(II) sulfate that will dissolve in 2.50 x 10^2 ml water. Ksp= 1.8 x 10^-8
ki77a [65]

Answer:

9.86*10^(-3) g

Explanation:

PbSO4 ----> Pb^(2+) + SO4^(2-)

                     s               s

Ksp = s²

s =√Ksp = √(1.8*10^-8) = 1.3*10^(-4) mol/L

The molar solubility PbSO4 = 1.3*10^(-4) mol/L.

2.50 *10^2 mL *1L/10³mL =0.250L

1.3*10^(-4)mol/L *0.250L*303.3 g/mol = 9.86*10^(-3) g

7 0
3 years ago
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