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3 years ago

Water traveling in a circular motion when heating up a example of

Chemistry

2 answers:

musickatia [10]3 years ago

7 0

B would be the answer

Naddik [55]3 years ago

7 0

Answer:

B.convection

Explanation:

Convection is the circular motion that happens when warmer air or liquid — which has faster-moving molecules, making it less dense — rises, while the cooler air or liquid drops down

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an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem

OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

$P\cdot V = n\cdot R\cdot T$ ,

$\displaystyle V = \frac{n\cdot R\cdot T}{P}$ .

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of moles of particles in this gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of $R$ will be $8.314$ if $P$ , $V$ , and $T$ are in SI units. Convert these values to SI units:

$P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa$ ;
$V$ shall be in cubic meters, $\rm m^{3}$ ;
$T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K$ .

Apply the ideal gas law:

$\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}$ .

4 0

3 years ago

Which element would have the largest radius; Br or Se? Explain

dusya [7]

The atomic radium increases to the left and downwards on the periodic table.
By that logic, Se has the largest radius.

5 0

2 years ago

Which of the following is an electrolyte? a. PbCl2 b. MgS c. HNO3 d. Al2(Cr2O7)3

Phoenix [80]

Answer: A: PbCl2

Hope dis helps!

8 0

3 years ago

What is the number of molecules of c2h5oh in a 3m solution that contains 4.00kg h2o?

Veronika [31]

The number of C2H5OH in a 3 m solution that contain 4.00kg H2O is calculate as below

M = moles of the solute/Kg of water

that is 3M = moles of solute/ 4 Kg
multiply both side by 4

moles of the solute is therefore = 12 moles

by use of Avogadro law constant

1 mole =6.02 x10^23 molecules

what about 12 moles

=12 moles/1 moles x 6.02 x10^23 = 7.224 x10^24 molecules

3 0

3 years ago

Helppppp meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Maru [420]

Answer:

The industry represented in the photo is most likely fishing. Other industries that rely on accurate weather forecasts are shrimping, fishery, and aquaculture

Explanation:

6 0

2 years ago

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Water traveling in a circular motion when heating up a example of￼

Water traveling in a circular motion when heating up a example of