Question

What volume in mL of a 2.9M solution is needed in order to prepare 2.3L of a 1.1M solution?

Answer 1

V - 0.87 liters I'm sure I'm right 

Answer 2

As i am reading the question, I notice they give two concentrations (M), one volume (L), and they are asking for another volume. this is a hint that you need to use the following formula

C1V1 = C2V2                (note: C stands for concentration)

C1= 2.9 M
V1= ?
C2= 1.1 M
V2= 2.3 L

now let's plug in the numbers

( 2.9 x V1)= (1.1 X 2.3)

V1= 0.87 Liters