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creativ13 [48]
3 years ago
10

What volume in mL of a 2.9M solution is needed in order to prepare 2.3L of a 1.1M solution?

Chemistry
2 answers:
Mumz [18]3 years ago
7 0
V - 0.87 liters I'm sure I'm right 
sladkih [1.3K]3 years ago
6 0
As i am reading the question, I notice they give two concentrations (M), one volume (L), and they are asking for another volume. this is a hint that you need to use the following formula

C1V1 = C2V2                (note: C stands for concentration)

C1= 2.9 M
V1= ?
C2= 1.1 M
V2= 2.3 L

now let's plug in the numbers

( 2.9 x V1)= (1.1 X 2.3)

V1= 0.87 Liters


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Answer:

neon is the Noble gas but I have not studied this much

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3 years ago
train travel from hong kong to beijing it traveled at an average speed of 160 km/m in the first 4 hours. after that it traveled
Nonamiya [84]

Answer:

7 hours

Explanation: step 1. 160x4=640

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5 0
3 years ago
Read 2 more answers
The atomic weight of copper is 63.546 amu. The two naturally occuring isotopes of copper have the following masses 63Cu, 62.9298
strojnjashka [21]

Answer:

The percent isotopic abundance of Cu-65 is 30.79 %.

The percent isotopic abundance of Cu-63 is 69.21 %.

Explanation:

we know there are two naturally occurring isotopes of carbon, Cu-63 (62.9298 amu)  and Cu-65 (64.9278 amu)

First of all we will set the fraction for both isotopes

X for the isotopes having mass 62.9298 amu

1-x for isotopes having mass 64.9278 amu

The average atomic mass of copper is 63.546 amu.

we will use the following equation,

62.9298 x + 64.9278 (1-x) = 63.546

62.9298x +  64.9278 -  64.9278x = 63.546

62.9298x - 64.9278x = 63.546  - 64.9278

-1.998 x = -1.3828

x=-1.3828 / -1.998

x= 0.6921

0.6921 × 100 = 69.21 %

69.21 % is abundance of Cu-63 because we solve the fraction x.

now we will calculate the abundance of Cu-65.

(1-x)

1-0.6921 = 0.3079

0.3079 × 100 = 30.79 %

30.79 % for Cu-65.

6 0
3 years ago
Which of the following is not a factor that affects thermal energy of a substance?
RideAnS [48]
The answer is : B. age of material

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7 0
3 years ago
How many moles are in 5.3 X 10^6 atoms of Calcium (Ca)?
iris [78.8K]

Answer:

8.801×10^-18 moles Ca

Explanation:

5.3 X 10^6atoms* (1mol/6.022*10^23) = 8.801×10^-18 moles Ca

5 0
3 years ago
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