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lyudmila [28]
3 years ago
14

Four preparations involving table sugar (sucrose) are described below. Analyze the sugar preparation processes and the end produ

cts.
Sugar Water Sugar Floss Sugar Caramel Rock Sugar

Sugar is added to water, and the water is stirred until the sugar is no longer visible. Sugar is melted and blown with a fan to make thin threads of solid sugar. Pure sugar is melted and cooked until it changes color and becomes a thick, sticky liquid. A highly concentrated solution of sugar water is prepared, large sugar crystals are allowed to form slowly, and then dye is added.


Which of the following is evidence that a chemical reaction has taken place in one of the processes?
A.
the slow growth of giant sugar crystals from a highly concentrated sugar-water solution and added dye
B.
the color change that takes place after heat melts and begins to decompose the sugar
C.
the melting and re-solidification of sugar into threads, which are different from sugar’s natural cube-shaped crystals
D.
the dissolution of solid sugar in water to form a thin, colorless, odorless liquid
Chemistry
1 answer:
MAXImum [283]3 years ago
4 0

Answer:

the answer is c

Explanation:

because i got it right

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A food product contains 15 g of carbohydrates (CHO), 5 g of protein (PRO), and 4 g of fat. How many calories are in one serving
ANEK [815]

Answer:

116 Cal  

Explanation:

15 g CHO × 4 Cal/g =   60 Cal

5 g PRO  × 4 Cal/g =   20

4 g fat     × 9 Cal/g = <u>  36     </u>  

                   TOTAL = 116 Cal

There are 116 Cal in one serving of the product.

6 0
3 years ago
Read 2 more answers
How many rings does an alkane have if its formula is c10h16?
stepladder [879]

If it is saturated compound then we can calculate the double bond equivalent which will be equal to the number of rings in the compound

the double bond equivalent can be calculated using following formula

DBE = (C + 1 -\frac{H}{2} - \frac{X}{2} +\frac{N}{2} )

Where

H = number of Hydrogen atoms

C = number of carbon atoms

X= number of halogen atoms

N = number of nitrogen atoms

DBE = (10 + 1  - 16 / 2 ) = 3

Hence there are three rings in the compound

3 0
3 years ago
The kidneys play a major role in the urinary system. Which of these is NOT a function of the kidneys?
Jet001 [13]

Answer:

C

Explanation:

3 0
3 years ago
The alkali metals play virtually the same general chemical role in all their reactions. (b) How is it based on atomic properties
vfiekz [6]

b) It is based on atomic properties as alkali metals requires 7 more electrons to complete their outer orbit. And they try to give those electrons to other elements to obtain noble gas configuration.

Noble gases are the gases which do not react easily with anything. They are also called as Inert gases, and belongs to group 18 of the periodic table.

Alkali metals are the substances which are found in Group I of a periodic table. Mostly the elements which are present are:

  • Lithium (Li)
  • Sodium (Na)
  • Potassium (K)
  • Rubidium (Rb)
  • Cesium (Cs)
  • Francium (Fr)

Properties of alkali metals are:  Soft, shiny reactive metals. They are soft enough to cut with knife. Metals react with water and air quickly and gets tarnish, so pure metals are stored in container by dipping them in oil to prevent oxidation.

To know more about Alkali metals, refer to this link:

brainly.com/question/18153051

#SPJ4

6 0
2 years ago
how many grams of calcium oxide will be produced in a closed vessel containing 20.0 kg of calcium and 20.0 kg of oxygen gas if t
sergejj [24]

Answer:

27984.1311 g  

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

<u>For calcium :- </u>

Mass of calcium = 20.0 kg = 20000 g ( 1 kg = 1000 g )

Molar mass of calcium = 40.078 g/mol

Thus,

Moles= \frac{20000\ g}{40.078\ g/mol}

Moles\ of\ calcium= 499.0269\ mol

<u>For oxygen gas :- </u>

Mass of oxygen gas = 20.0 kg = 20000 g ( 1 kg = 1000 g )

Molar mass of oxygen gas = 31.999 g/mol

Thus,

Moles= \frac{20000\ g}{31.999\ g/mol}

Moles\ of\ oxygen\ gas= 625.0195\ mol

According to the given reaction:

2Ca+O_2\rightarrow 2CaO

2 moles of calcium reacts with 1 moles of oxygen gas

Also,

1 mole of calcium react with 1/2 mole of oxygen gas

So,

499.0269 mole of calcium react with \frac{1}{2}\times 499.0269 mole of oxygen gas

Moles of oxygen gas = 249.5135 moles

Available moles of oxygen gas = 625.0195 moles

Limiting reagent is the one which is present in small amount. Thus, calcium is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

2 moles of calcium produces 2 moles of calcium oxide

So,

1 mole of calcium produces 1 mole of calcium oxide

Also,

499.0269 mole of calcium produces 499.0269 mole of calcium oxide

Moles of calcium oxide = 499.0269 moles

Molar mass of calcium oxide = 56.0774 g/mol

Mass of calcium oxide = Moles × Molar mass = 499.0269 × 56.0774 g = 27984.1311 g  

<u>27984.1311 g  of calcium oxide will be produced.</u>

8 0
4 years ago
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