4Ag + 2H2S + O2 -> 2Ag2S + 2H20 i’m pretty sure that’s correct
When a molecule can occupy the same active site as the substrate, a situation called enzymes can result.
A: adenine
C: cytosine
g: guanine
t: thymine
Answer:
The correct answer to the question is
The standard heat of reaction for the reaction is
a. 216.8 kJ released per mole
Explanation:
The heat of reaction is given by [Heat of formation of products] - [Heat of formation of reactants]
In the question we have, heat of formation of the products Zn+2 (aq) = -152.4 kJ/mole and the heat of formation of the reactants = 64.4 kJ/mole
Therefore, the heat of formation of the reaction = (-152-64.4) kJ/mole or
-216.8 kJ/mole released
Answer:
92.49 %
Explanation:
We first calculate the number of moles n of AgBr in 0.7127 g
n = m/M where M = molar mass of AgBr = 187.77 g/mol and m = mass of AgBr formed = 0.7127 g
n = m/M = 0.7127g/187.77 g/mol = 0.0038 mol
Since 1 mol of Bromide ion Br⁻ forms 1 mol AgBr, number of moles of Br⁻ formed = 0.0038 mol and
From n = m/M
m = nM . Where m = mass of Bromide ion precipitate and M = Molar mass of Bromine = 79.904 g/mol
m = 0.0038 mol × 79.904 g/mol = 0.3036 g
% Br in compound = m₁/m₂ × 100%
m₁ = mass of Br in compound = m = 0.3036 g (Since the same amount of Br in the compound is the same amount in the precipitate.)
m₂ = mass of compound = 0.3283 g
% Br in compound = m₁/m₂ × 100% = 0.3036/0.3283 × 100% = 0.9249 × 100% = 92.49 %