Answer:
A. Time, t = 4.35s
B. Height of its fall, S = 92.72m
Explanation:
Vo = 0 m/s
Vi = 0.46h m/s
S = h m
a = 9.81 m/s2
To calculate the time taken, we need to get the value of the distance, h.
Using the equations of motion,
Vi^2 = Vo^2 + 2aS
Where Vi = final velocity
Vo = initial velocity
a = acceleration due to gravity
S = height of its fall
(0.46h)^2 = 0 + 2*9.81*h
0.2116h^2 = 19.62h
h = 19.62/0.1648
= 92.722 m
To calculate the time,
S = Vo*t +(1/2)*a*t^2
92.772 = 0 + (1/2)*9.81*t^2
t^2 = 185.44/9.81
= 18.904
t = sqrt(18.904)
= 4.348 s
Because real electrons are in an electron cloud, not layers
Answer:
Explanation:
Given:
mass of the boat,
uniform speed of the boat,
rate of accumulation of water mass in the boat,
time of observation,
The mass of the boat after the observed time:
<u>Now using the conservation of momentum:</u>
S = ut + 0.5at^2
s = distance which is height (down)
u = original veocity = 0
t = time = 2.5 s
a = g = 10m/s^2 ; free fall (down)