The dimension of soccer field in ft is 377.315 ft long and 277.885 ft in width.
The dimension of soccer field in ft is 4527.78 in long and 3334.62 in in width.
As it is given that 1 m =3.281 ft
Therefore the length of the soccer field in ft is
115*3.281=377.315 ft
And width of the field is 85*3.281=277.885 ft
We know that 1 ft =12 in
Therefore the length of the soccer field in in is
377.315*12=4527.78 in
And width of the field is 277.885 *12=3334.62 in
Answer:
Fint = - 67.094 N
Explanation:
Given
W = 71.4 N
∅ = 20º
Fint = ?
The interaction partner of the Normal Force has equal magnitude and opposite direction to the Normal Force, and it is a contact force exerted by the crate on the ramp, because the interaction parteners are the same force acts on the two object.
Then: Fint = - N = - Wy' = - W*Cos ∅
⇒ Fint = - 71.4 N*Cos 20º = - 67.094 N
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Answer:
Explanation:
From the question we are told that:
Dimension of plate:
Depth submerged
Water density
Gravity
Generally the equation for Volume is mathematically given by
Therefore The mass of Plate is
Generally the equation for Force on the plate is mathematically given by
F=ma