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goldfiish [28.3K]
3 years ago
11

The vitreous humor, a transparent, gelatinous fluid that fills most of the eyeball, has an index of refraction of 1.34. Visible

light ranges in wavelength from 400 nm (violet) to 700 nm (red), as measured in air. This light travels through the vitreous humor and strikes the rods and cones at the surface of the retina. What are the ranges of:
(a) The wavelength inside the vitreous humor?
(b) The frequency?
Physics
1 answer:
Leto [7]3 years ago
4 0

Answer:

a)   298.5 nm ,  522.4 nm  and b)  radiation frequency does not change

Explanation:

When electromagnetic radiation reaches a medium with a different index of refraction, the medium vibrates the molecules, as if it were a resonance process, whereby the medium vibrates at the same frequency as the incident light.

On the other hand, when the light reaches another medium its average speed within the medium changes, it is now less than the speed of light in a vacuum (c) for this to happen as we saw that the frequency is constant there must be a change in the wavelength of the radiation that is characterized by the ratio

    λₙ = λ₀ / n

    λₙ = 400 nm    in the void

    λₙ = 400 / 1.34

    λₙ= 298.5 nm

   λ₀ = 700 nm

   λₙ = 700 / 1.34

   λₙ = 522.4 nm

The radiation frequency does not change

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While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? (Reme
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4 0
2 years ago
Millikan is doing his oil drop experiment. He has a droplet with radius 1.6 µm suspended motionless in a uniform electric field
swat32

Answer:

The charge on the droplet is 3.106\times10^{-16}\ C.

Yes, quantization of charge is obeyed within experimental error.

Explanation:

Given that,

Radius = 1.6μm

Electric field = 46 N/C

Density of oil = 0.085 g/cm³

We need to calculate the charge on the droplet

Using formula of force

F= qE

mg=qE

V\times\rho\times g=qE

q=\dfrac{V\times\rho}{E}

q=\dfrac{\dfrac{4}{3}\pi\times r^3\times\rho\times g}{E}

Put the value into the formula

q=\dfrac{\dfrac{4}{3}\times\pi\times(1.6\times10^{-6})^3\times85\times9.8}{46}

q=3.106\times10^{-16}\ C

We need to calculate the quantization of charge

Using formula of quantization

n = \dfrac{q}{e}

Put the value into the formula

n=\dfrac{3.106\times10^{-16}}{1.6\times10^{-19}}

n=1941.25

Yes, quantization of charge is obeyed within experimental error.

Hence, The charge on the droplet is 3.106\times10^{-16}\ C.

Yes, quantization of charge is obeyed within experimental error.

7 0
3 years ago
Read 2 more answers
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