Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.
<h3>What is Work done?</h3>
Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;
W = f × d
Where f is force applied and d is distance travelled.
Given that;
- Work done W = 3500J = 3500kgm²/s²
- Distance covered d = 1.5m
- Force applied F = ?
W = f × d
3500kgm²/s² = f × 1.5m
f = 3500kgm²/s² ÷ 1.5m
f = 2.3 × 10³ kgm/s²
f = 2.3 × 10³ N
Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.
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Answer:
Between -35 degrees C and 355 degrees C
Explanation:
At any temperature between, but not including the freezing and boiling points, the substance would be in its liquid state.
Information provided:
Length of wire, L = 320 m
Current through the wire, I = 120 Amps
Earth's magnetic field acting on the wire, B = 5.0*10^-5 T
Angle at which the magnetic field acts, Ф = 60°
By definition;
Force on the wire, F = LBI Sin Ф
Substituting;
F = 320*5*10^-5*120*Sin 60 = 1.663 N
According to momentum conservation
15*3 = 45kgm/s
and the velocity of 5 kg mass will be
45/5 = 9 m/s
Answer:
The ratio between W2 and W1 is
p=1.5
Explanation:
The W2/W1 ratio equals the efficiency ratio, since the heat input is constant.
Initially, the Carnot efficiency is
1 - (Tc/Th)
1 - 400/800 = 0.50
After lowering Tc, the efficiency becomes
1 - (Tc/Th)
1 - 200/800 = 0.75
So to determine the ratio between W2 and W1
W2/W1 = 0.75/0.50 = 1.5