Answer:
The volume of the lungs at 5m deep is 4L
Explanation:
Hello!
We can solve this problem considering that the air inside de lungs behave as an ideal gas, and that the temperature is the same at sea leavel and 10 m below the surface, in this case:
P1 V1 = P2 V2 -- (1)
wher P and V stands for pressure and volume, and 1 and 2 for the intial (sea level) and final (5m below) states.
We know that:
P1 = 14.7 psi
V1 = 6 L
And if the pressure exerted by the water adds 14.7 psi to atmospheric pressure so 10 m below the surface, then at 5 m below it must add 14.7/2 psi, therefore:
P2 = (14.7/2) psi + atmospheric pressure = 7.35 psi + 14.7 psi
P2 = 22.05 psi
Solving equation (1) for V2:
V2 = V1 (P1/P2) = 6 L (14.7 psi / 22.05 psi ) = 6 *(2/3) = 4 L
The volume of the lungs at 5m deep is 4L
Answer:
the wave length becomes doubled or becomes two times the initial wavelength = 240 cm
Explanation:
From wave,
v = λf................ Equation 1
Where v = velocity of the wave, λ = wavelength of the wave, f = frequency of the wave.
Given: f = 1200 Hz, λ = 120 cm = 1.2 m
Substitute into equation 1
v = 1200(1.2)
v = 1440 m/s.
When the ship sent out a 600 Hz sound wave,
make λ the subject of formula in equation 1
λ = v/f............. Equation 2
Given: f = 600 Hz, v = 1440 m/s
Substitute into equation 2
λ = 1440/600
λ = 2.4 m or 240 cm.
When the ship sent out a 600 Hz sound wave instead, the wave length becomes doubled or becomes two times the initial wavelength = 240 cm
You use the equation potential energy= mass x gravity x height. 10x2x9.8=196.
Answer:
A solenoid is a type of electromagnet, the purpose of which is to generate a controlled magnetic field through a coil wound into a tightly packed helix. The coil can be arranged to produce a uniform magnetic field in a volume of space when an electric current is passed through it.
Answer:
a) If we apply pressure to a fluid in a sealed container, the pressure will be felt undiminished at every point in the fluid and on the walls of the container.
Explanation:
Pascal´s Principle can be applied in the hydraulic press:
If we apply a small force (F1) on a small area piston A1, then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F2) can be exerted that is proportional to the area(A2) of the piston.
P=F/A
P1=P2
F1/ A1= F2/ A2
F2= F1* A2/ A1
The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.
In an incompressible liquid, the volume and amount of mass does not vary when pressure is applied.