3•2•7=42•2=84
12•10•7=840
84+840=924in^3
9514 1404 393
Answer:
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.
(1) 2 of one step equations
x - 23 = 8
x - 23 + 23 = 8 + 23
x = 31
n + 2 = 9
n + 2 - 2 = 9 - 2
n = 7
(2) 2 equations with fractions
3/4 (x + 3) = 9
4 [ 3/4 (x + 3) ] = 4[9]
3 (x + 3) = 36
3x + 9 - 9 = 36 - 9
3x/3 = 27/3
1/3 x 3/4
cross multiply
so 3/12 and simplify which makes it
1/4
(3) distributive property
3(2 + 4) = (3 • 2) + (3 • 4)
3(6) = 6 + 12
18 = 18