What is ionization energy? What is fist ionization energy?

1 answer:

8 0

The ionization energy is the minimum amount of energy required to remove the most loosely bound electron of an isolated neutral gaseous atom or molecule.The first ionisation energy is the energy required to remove one mole of the most loosely held electrons from one mole of gaseous atoms to produce 1 mole of gaseous ions each with a charge of 1+. I hope this helps :3

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How many grams are in 1.25 moles of Potassium hydroxide, KOH? 1 point

klasskru [66]

Answer:

There are 70 grams of KOH

Explanation:

First, we calculate the weight of 1 mol of KOH:

Weight 1 mol KOH: Weight K + Weight 0 + Weight H= 39g+ 1g+ 16g= 56 g/mol

1 mol-------56 g KOH

1,25 mol----x= (1,25 molx56 g KOH)/1 mol= 70 g KOH

7 0

3 years ago

An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d = 1.114 g/ml; = 62.07 g/mol) and water (d

tankabanditka [31]

a) Volume percent

Formula: % v/v = [volume solute / volume solution] * 100

Just to make it easy take a base of 50 volume parts of ethylen glycol and 50 volume parts of water to make 100 volumes of mixture (this assumpion will be valid for all the questions):

% v/v =[ 50 ml ethyleneglycol] / [100 ml mixture] * 100 = 50%

Answer: 50% v/v

b) Mass percent

% m/m = [mass ethylene glycol / mass solution] * 100

mass ethylene glycol = 50 ml * 1.114 g/ ml = 55.7 g

mass of mixture = 100 ml * 1.07 g/ml = 107 g

% m/m = [55.7 / 107 g] * 100 = 52.06 %

Answer: 52.06%

c) Molarity

M = number of moles of solute / liters of solution

number of moles of solute = mass in grams / molar mass

number of moles of ehtylene glycol = 55.7 g / 62.07 g/mol = 0.8974 mol

liters of solution = 0.1 liter

M = 0.8974 mol / 0.1 liter = 8.974 M

Answer: 8.974 M

d) Molality

m = number of moles of solute / kg of solvent

number of moles of ethylen glycol = 0.8974 mol

mass of water = 50 ml * 1 g/ml = 50 g = 0.05 kg

m = 0.8974 mol / 0.05 kg = 17.95 m

Answer: 17.95 m

e) mole fraction

mole fraction = [number of moles of solute] / [number of moles of mixture] * 100

number of moles of ethylen glycol = 0.8974 mol

number of moles of water = 50 g / 18.01 g /mol = 2.776 mol

mole fraction = 0.8974 mol / [0.8974 mol + 2.776 mol] = 0.244

Answer: 0.244

7 0

3 years ago

True or false ? an insoluble base will react with an acid.

Leno4ka [110]

Answer:

true maybe

Explanation:

#CarryOnLearning

7 0

3 years ago

For H3PO4, Ka1 = 7.3 x 10^-3, Ka2 = 6.2 x 10^-6, and Ka3 = 4.8 x 10^-13. A 0.10 M aqueous solution of Na3PO4 therefore would be

zmey [24]

Answer:

The aqueous solution of $Na_{3} Po_{4}$ therefore would be "strongly basic."

Explanation:

Strongly basic because the $Na_{3} Po_{4}$ is completely an ionic compound. These compound can be 100% splitted into metal ions and hydroxide ion when used in the aqueous solution. Each moles dissolves which can give rise to mole of hydrogen ions when used in the solution. Whereas strong bases are not soluble in water as well. in the presence of water equilibrium can also be achieved. A strong base has the capability which can just remove the proton from the molecule.

3 0

3 years ago

Need help and people to show their work

AlekseyPX

It is 292.5 m because you do 4.5 hours times 65. (please give me brainliest)

6 0

3 years ago