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lbvjy [14]
4 years ago
6

A student conducts an investigation to determine which magnet is strongest: the horseshoe, the bar, or the ring. The student tes

ts each magnet one time using the same metal object and announces that the bar magnet is strongest. What is wrong with the student's reasoning?
Chemistry
2 answers:
evablogger [386]4 years ago
8 0

Answer:

Each magnet should have been tested on many different magnetizable materials

Explanation:

In designing an experiment such as that outlined above, the experimental design should have included many different magnetizable materials.

All the types of magnets; the horseshoe, the bar, and the ring magnet should have been tested using many different magnetizable materials apart from the metal object. By so doing, the strongest magnet can be effectively determined without bias because it will attract the greatest number of magnetizable materials.

Again, the shape of the magnet affects its ability to attract objects. Hence, different shapes of magnets can not effectively be compared for relative magnetic strength.

Mila [183]4 years ago
6 0

Explanation:

bold is strong

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When two or more substances are physically combined the result is a:.
sp2606 [1]

Answer:

I think it is called a Mixture

Explanation:

Sorry if it is wrong

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3 years ago
ILL MARK BRAINLIEST :)
DanielleElmas [232]

Explanation:

According to the law of conservation of mass, mass can neither be created nor destroyed but it can simply be transformed from one form to another.

For example, Na^{+} + Cl^{-} \rightarrow NaCl

Mass of Na = 23 g/mol

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Sum of mass of reactants = mass of Na + mass of Cl

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Mass of product formed is as follows.

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3 years ago
Which formula represents Carbonic acid
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Answer:

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8 0
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which equation is setup correctly to determine the volume of a 1.5 mol sample of oxygen gas at 22 degrees Celsius and 100 kPa
rjkz [21]
Hello!

We have the following data:


v (volume) = ? (in L)
n (number of mols) = 1,5 mol
T (temperature) = 22 ºC 
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15

P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K

<span>We apply the data above to the Clapeyron equation (gas equation), let's see:

</span>P*V = n*R*T

0,987*V = 1,5*0,082*295,15

0,987V = 36,30345

V =  \dfrac{36,30345}{0,987}

\boxed{\boxed{V \approx 36,78\:L}} \end{array}}\qquad\checkmark

I hope this helps. =)
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Answer:

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