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devlian [24]
2 years ago
5

If you added enough ropes and pulleys to lift any size mass would it be possible to never have to apply a force to move your mas

s? Why or Why Not? Explain your answer using scientific terms we have been learning.
pls help!!
Physics
2 answers:
tatiyna2 years ago
7 0

Answer:

we have to apply force to move something things wants to save their position and if we want to change it

we have too apply force

Ira Lisetskai [31]2 years ago
3 0

Answer:

we have to apply

them to have a answer

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What are used for manufacturing paper along with wood and chemicals
Tju [1.3M]

Answer:

Paper and pulp are made from cellulosic fibers and other plant materials. Some synthetic materials may be used to impart special qualities to the finished product. Paper is made from wood fibers, but rags, flax, cotton linters, and bagasse are also used in some papers.

8 0
3 years ago
Given: Q1 = +10 uc = 1.0 x 10-5C
ser-zykov [4K]

Answer:

-0.038 N

Explanation:

F=K Q1 Q2/r^2 by COULOMB'S LAW

F= 9×10^9×1×10^-5×-1.5×10^-5/(6)^2

F= -0.038 N

5 0
2 years ago
Ryan is driving home from work and notices a deer leaping onto the road about 25 m in front of his car. He immediately applies t
Anvisha [2.4K]

Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

v^2=v_0^2+2ax\\

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

    = 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

F_f=ma=(1490kg)(5.55m/s^2)=8271.15N

Furthermore, you use the relation between the friction force and the friction coefficient:

F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56

hence, the friction coefficient is 0.56

6 0
2 years ago
You have a battery marked " 6.00 V 6.00 V ." When you draw a current of 0.383 A 0.383 A from it, the potential difference betwee
Archy [21]

Answer:

V = 4.81 V

Explanation:

  • As the potential difference between the battery terminals, is less than the rated value of the battery, this means that there is some loss in the internal resistance of the battery.
  • We can calculate this loss, applying Ohm's law to the internal resistance, as follows:

        V_{rint} = I* r_{int}

  • The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:

       V = V_{b} - V_{rint}  = 5.03 V = 6.0 V - 0.383 A* r_{int}

  • We can solve for rint, as follows:

         r_{int} = \frac{V_{b}-V}{I} =\frac{6.0V-5.03V}{0.383A} = 2.53 \Omega

  • When the circuit draws from battery a current I of 0.469A, we can find the potential difference between the terminals of the battery, as follows:

       V = V_{b} - V_{rint}  = 6.0 V - 0.469 A* 2.53 \Omega= 6.0 V - 1.19 V = 4.81 V

  • As the current draw is larger, the loss in the internal resistance will be larger too, so the potential difference between the terminals of the battery will be lower.
5 0
3 years ago
How can we maximise the rate of energy transfer to keep things cool?
faltersainse [42]
To do this we may use things that are good conductors - are painted dull black -
Have a air flow around them Maximised.


6 0
3 years ago
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