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sesenic [268]
4 years ago
7

How much power does a toaster have if it does 21,000 joules of work in 30 seconds?

Physics
1 answer:
marysya [2.9K]4 years ago
5 0

Power  =  (work done)  /  (time to do the work)

           =  (21,000 Joules)  /  (30 seconds)

           =   (21,000 / 30)  joule/sec

           =      700   watts  
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The correct answer is Light years
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If a sinusoidal electromagnetic wave with intensity 18 W/m2 has an electric field of amplitude E, then a 36 W/m2 wave of the sam
Neporo4naja [7]

Answer:

The  correct option is D

Explanation:

From the question we are told that

  The intensity of the first  electromagnetic wave is  I =  18 \  W/m^2

  The amplitude of the electric field is  E_{max}_1 =A

   The intensity of the second electromagnetic wave is  I =  36 \  W/m^2

Generally the an electromagnetic wave intensity is mathematically represented as

       I  =  \frac{1}{2} *  \epsilon_o  * c  * E_{max}^2

Looking at this equation we see that

     I \ \ \alpha  \ \ E^2_{max}

=>  \frac{I_1}{I_2}  =  [ \frac{ E_{max}_1}{ E_{max}_2} ] ^2

=>   E_{max}_2 = \sqrt{\frac{x}{y} }  *  E_{max}_1

=>  E_{max}_2 = \sqrt{\frac{36}{18} }  * E        

=>  E_{max}_2 = \sqrt{2 }  E        

5 0
3 years ago
A uniform meter stick is pivoted at the 50.00 cm mark on the meter stick. A 400.0 gram object is hung at the 20.0 cm mark on the
babunello [35]

Answer:C

Explanation:

Given

mass m_1=400\ gm is at x=20\ cm mark

mass m_2=320\ gm is at x=75\ cm mark

Scale is Pivoted at x=50\ cm mark

For scale to be in equilibrium net torque must be equal to zero

Taking ACW as positive thus

T_{net}=0.4\times g\times (0.5-0.2)-0.32\times g\times(0.75-0.50)

T_{net}=0.12g-0.08g=0.04g

Therefore a net torque of 0.04 g is required in CW sense which a mass 400\ gm can provide at a distance of x_o from pivot

0.04g=0.4\times g\times x_o

x_o=0.1\ m

therefore in meter stick it is at a distance of x=60\ cm

6 0
3 years ago
A small plastic sphere of mass 2.0 g is charged to −5.0 nC and held 2.5 cm above a small glass bead of mass 0.015 g resting on a
LenKa [72]

Answer:uhhh

Explanation:

Uhhhh

5 0
4 years ago
The tub of a washer goes into its spin-dry cy-cle, starting from rest and reaching an angularspeed of 3.1 rev/s in 10.7 s.At thi
neonofarm [45]

Answer:

35 revolutions

Explanation:

t = Time taken

\omega_f = Final angular velocity

\omega_i = Initial angular velocity

\alpha = Angular acceleration

\theta = Number of rotation

Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{3-0}{10.7}\\\Rightarrow \alpha=0.28037\ rev/s^2

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{3.1^2-0^2}{2\times 0.28037}\\\Rightarrow \theta=17.13806\ rev

Number of revolutions in the 10.7 seconds is 17.13806

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-3.1}{11.2}\\\Rightarrow a=-0.27678\ rev/s^2

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-3.1^2}{2\times -0.27678}\\\Rightarrow \theta=17.36035\ rev

Number of revolutions in the 11.2 seconds is 17.36035

Total total number of revolutions in the 21.9 second interval is 17.13806+17.36035 = 34.49841 = 35 revolutions

3 0
4 years ago
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