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3 years ago

Which is a way that the elements are grouped on the periodic table? (2 points)

2 answers:

5 0

I think the correct answer from the choices listed above is the second option. A way that the elements are grouped on the periodic table would be that elements with similar bonding properties are in the same column. Each column is called a group. The elements in each group have the same number of electrons in the outer orbital.

Zarrin [17]3 years ago

4 0

the answer i think would be right is the second option, bonding

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How many protons does gold have

shusha [124]

Answer:

gold has 79 protons

Explanation:

i looked it up lol

8 0

3 years ago

40 g of CaCO3 is how many moles of CaCO3? 10 moles 0.4 moles 40 moles 100 moles

AleksandrR [38]

Answer:

0.4 moles

Explanation:

To convert between moles and grams you need the molar mass of the compound. The molar mass of of CaCO3 is 100.09g/mol. You use that as the unit converter.

40gCaCO3* 1mol CaCO3/100.09gCaCO3 = 0.399640 mol CaCO3

This rounds to 0.4 moles CaCO3

8 0

3 years ago

CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7

padilas [110]

Answer: The $\Delta G$ for the reaction is 54.425 kJ/mol

Explanation:

For the given balanced chemical equation:

$CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)$

We are given:

$\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol$

To calculate $\Delta G^o_{rxn}$ for the reaction, we use the equation:

$\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]$

For the given equation:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J$

Conversion factor used = 1 kJ = 1000 J

The expression of $K_p$ for the given reaction:

$K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}$

We are given:

$p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm$

Putting values in above equation, we get:

$K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85$

To calculate the gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_p$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = $8.314J/K mol$

T = Temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

$\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol$

Hence, the $\Delta G$ for the reaction is 54.425 kJ/mol

7 0

3 years ago

Plz help me!! Let it be a good amount of presentation.

Svetllana [295]

Answer:

Read the article on Mine Tools called "Active Listening"

Explanation:

Ive used it before for assignments. Its pretty informative and only takes like 10 minutes to read

5 0

3 years ago

Why does the temperature not change

S_A_V [24]

Answer:

Option A

Explanation:

Temperature of a body is due to the heat gained or loss. During a phase change, the atoms or molecules of a substance are undergoing change is temperature due to which no temperature change is observed during phase change. The heat in the transition phase is used to break bonds and the change in temperature is felt when kinetic energy change is complete. During transition, the average kinetic energy of the molecules remains unchanged and hence during a phase change a temperature do not changes until unless the phase change is completed.

Hence, option A is correct

6 0

3 years ago