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garik1379 [7]
2 years ago
8

Beaker contain 200 mL of water what is volume of water in cm cube and m cube

Physics
2 answers:
Rainbow [258]2 years ago
7 0

1 mL = 1 cm³

1 cm³ = 0.000 001 m³

200 mL = 200 cm³

200 cm³ = 0.000 2 m³

It can be ANY substance. It doesn't have to be water.

maksim [4K]2 years ago
6 0

<u><em>Part 1:</em></u>

<u>The basics of conversions state that:</u>

1 ml is equivalent to 1 cm³

This means that the ratio between them is 1:1

Therefore, 200 ml of water would be equivalent to 200 cm³ of water

<u><em>Part 2:</em></u>

<u>Again, the basics of conversion states that:</u>

1 ml is equivalent to 1 * 10⁻⁶ m³

We will use cross multiplication to convert 200 ml to m³ as follows:

1 ml ................> 1 * 10⁻⁶ m³

200 ml .........> ??

200 ml = \frac{200*1*10^{-6}}{1}  = 0.0002 m³

Hope this helps :)

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A 32-cm-long solenoid, 1.8 cm in diameter, is to produce a 0.30-T magnetic field at its center. If the maximum current is 4.5 A,
daser333 [38]

Answer:

<h2>16,931 turns</h2>

Explanation:

The magnetic field produced is expressed using the formula

B = \frac{\mu_0NI}{L}

B is the magnetic field = 0.30T

I is the current produced in the coil = 4.5A

\mu_0 is the magnetic permittivity in vacuum = 1.26*10^-6Tm/A

L is the length of the solenoid = 32 cm = 0.32 m

N is the number of turns in the solenoid.

Making N the subject of the formula from the equation above;

B = \frac{\mu_0NI}{L}\\\\BL = \mu_0NI\\\\Dividing\ both\ sides \ by \ \mu_0I\\\\\frac{BL}{\mu_0I} =\frac{\mu_oNI}{\mu_0I} \\\\

N = \frac{BL}{\mu_0I}

Substituting the give values to get N;

N = \frac{0.3*0.32}{1.26*10^{-6} * 4.5}\\\\N = \frac{0.096}{0.00000567} \\\\N = 16,931.21

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4 0
3 years ago
The great limestones caverns were formed by dripping water. If water droplets of 10 ml fall from a height of 5 m at a rate of 10
loris [4]

The average force of the water droplets is the force given by the impact

per second of the droplets on the limestone floor.

  • The average force exerted on the limestone floor is approximately <u>1.6013 × 10⁻² N</u>

Reasons:

The given parameters are;

Volume of a droplet = 10 ml = 1 × 10⁻⁵ m³

Height from which the water falls, <em>h </em>= 5 meters

Rate at which the water falls = 10 per minute

Required:

The average force exerted on the floor by the water droplets.

Solution:

According to Newton's Second Law of motion, we have;

Force = Rate of change of momentum

Momentum = Mass × Velocity

Mass of a droplet of water = Volume × Density

Density of water = 997 kg/m³

Mass of a droplet = 1 × 10⁻⁵ m³ × 997 kg/m³ = 0.00997 kg

The velocity just before the droplet reaches the ground, v = √(2·g·h)

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Which gives;

v = √(2 × 9.81 m/s² × 5 m) ≈ 9.905 m/s

The rate of change in momentum per minute = 1

Therefore;

\displaystyle The \ rate \ of \ change \ in \ momentum = Average \ force = \mathbf{\frac{\Delta Momentum }{\Delta Time}}

ΔMomentum = Mass × ΔVelocity

Considering the 10 drops per minute, we have;

ΔMomentum = 10 × 0.0097 kg × 9.905 m/s = 0.960785 kg·m/s

ΔTime = 1 minute = 60 seconds

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\displaystyle Average \ force, \, F_{ave}  \frac{0.960785 \, kg\cdot m/s }{60 \, s} \approx =\mathbf{1.6013 \times 10^{-2} \, N}

  • The average force exerted on the limestone floor by the droplets of water is F_{ave} ≈ <u>1.6013 × 10⁻² N</u>

Learn more about Newton's Second Law of motion and force exerted water here:

brainly.com/question/3999427

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I would believe it to be C. Gold, but I'm not quite sure
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The ball has 7.35 joules of potential energy at position B. At position A, all of the energy changes to kinetic energy. The velo
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I assume that the ball is stationary (v=0) at point B, so its total energy is just potential energy, and it is equal to 7.35 J. 
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And since K=7.35 J, we can find the velocity, v:
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Hihi!

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