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Luba_88 [7]
3 years ago
5

Jonathan used the following soil triangle to identify a sample of soil as sandy clay. Which description of soil likely allowed J

onathan to make this identification.
A. Mostly large grains, with a sticky texture, 55% sand, 40% clay, 5% silt.
B. Mostly large grains, with a gritty texture, 45% sand, 5% clay, 45% silt.
C. Mostly small grains, with a smooth texture, 30% sand, 5% clay, 65% silt.
D. Mostly small grains, with a sticky texture, 30% sand, 50% clay, 20% silt.

Chemistry
1 answer:
Papessa [141]3 years ago
7 0

Answer:

Mostly large grains, with a sticky texture, 55% sand, 40% clay, and 5% silt

Explanation: I took the test, hope it helps.

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A 2.50 g sample of solid sodium hydroxide is added to 55.0 mL of 25 °C water in a foam cup (insulated from the environment) and
zlopas [31]

Answer:

37.1°C.

Explanation:

  • Firstly, we need to calculate the amount of heat (Q) released through this reaction:

<em>∵ ΔHsoln = Q/n</em>

no. of moles (n) of NaOH = mass/molar mass = (2.5 g)/(40 g/mol) = 0.0625 mol.

<em>The negative sign of ΔHsoln indicates that the reaction is exothermic.</em>

∴ Q = (n)(ΔHsoln) = (0.0625 mol)(44.51 kJ/mol) = 2.78 kJ.

  • We can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released to water (Q = 2781.87 J).

m is the mass of water (m = 55.0 g, suppose density of water = 1.0 g/mL).

c is the specific heat capacity of water (c = 4.18 J/g.°C).

ΔT is the difference in T (ΔT = final temperature - initial temperature = final temperature - 25°C).

∴ (2781.87 J) = (55.0 g)(4.18 J/g.°C)(final temperature - 25°C)

∴ (final temperature - 25°C) = (2781.87 J)/(55.0 g)(4.18 J/g.°C) = 12.1.

<em>∴ final temperature = 25°C + 12.1 = 37.1°C.</em>

6 0
3 years ago
How many photons are produced in a laser pulse of 0.364 J at 477 nm?
Luda [366]

Answer:

1.00 × 10¹⁸

Explanation:

1. Calculate the <em>energy of one photon</em>

The formula for the energy of a photon is

<em>E</em> = <em>hc</em>/λ  

<em>h</em> = 6.626 × 10⁻³⁴ J·s; <em>c</em> = 2.998 × 10⁸ m·s⁻¹

λ = 477 nm = 477 × 10⁻⁹ m                              Insert the values

<em>E</em> = (6.626 × 10⁻³⁴ × 2.998× 10⁸)/(477 × 10⁻⁹)

<em>E</em> = 4.165× 10⁻¹⁹ J

2. Calculate the <em>number of photons</em>

Divide the total energy by the energy of one photon.

No. of photons = 0.418 × 1/4.165 × 10⁻¹⁹      

No. of photons = 1.00 × 10¹⁸

7 0
3 years ago
Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B How many boxes of B would be required to make 30
Iteru [2.4K]
Mass box C is 10+5. (So C is 15)

But if C was 30, how many times could you put B (5) into it?

30/5 = 6

You would need 6 boxes of B to make 30 grams of C.
5 0
3 years ago
Read 2 more answers
How many atoms are in 4.93 moles hcl?
trasher [3.6K]
1 mole ------------- 6.02x10²³ atoms
4.93 moles ------- ??

4.93 x ( 6.02x10²³) / 1 = 

=> 2.96x10²⁴ atoms
4 0
3 years ago
What would be the volume of 0.500 mole of an ideal gas at a temperature of 273.15 Kelvins and 1 atm?
uysha [10]

Answer:

V = 11.21 L

Explanation:

Given data:

Volume of helium = ?

Number of moles = 0.500 mol

Temperature = 273.15 K

Pressure of gas = 1 atm

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

V = nRT/P

V = 0.500 mol ×  0.0821 atm.L/ mol.K  × 273.15 K / 1 atm

V = 11.21 L / 1

V = 11.21 L

8 0
3 years ago
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