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3 years ago

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Which two elements have the most similar chemical properties? 1. beryllium and magnesium 2. hydrogen and helium 3. phosphorus an

d sulfur 4. potassium and strontium

2 answers:

tatiyna3 years ago

7 0

Phosphorus and sulphur is the answer

Mazyrski [523]3 years ago

4 0

beryllium and magnesium is your answer

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A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

What is the chemical formula for 2-propanol?

monitta

i think the answer is C3H8O

8 0

3 years ago

. a large piece of jewelry has a mass of 132.6 g. a graduated cylinder initially contains 48.6 ml water. when the jewelry is sub

elena-s [515]

The large piece of jewelry that has a mass of 132.6 g and when is submerged in a graduated cylinder that initially contains 48.6 ml water and the volume increases to 61.2 ml once the piece of jewelry is submerged, has a density of: 10.523 g/ml

To solve this problem the formulas and the procedures that we have to use are:

v = v(f)-v(i)
d = m/v

Where:

d= density
m= mass
v= volume
v(f) = final volume
v(i) = initial volume

Information about the problem:

m = 132.6 g
v(i) = 48.6 ml
v(f) = 61.2 ml
v = ?
d =?

Applying the volume formula we get:

v = v(f)-v(i)

v = 61.2 ml - 48.6 ml

v = 12.6 ml

Applying the density formula we get:

d = m/v

d = 132.6 g/12.6 ml

d = 10.523 g/ml

<h3>What is density?</h3>

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

Learn more about density in: brainly.com/question/1354972

#SPJ4

3 0

1 year ago

If the temperature of a gas is increased from 20°C to 35°C, what is the new pressure if the original pressure was 1.2 atm? Assum

Marta_Voda [28]

Answer:

B.) 1.3 atm

Explanation:

To find the new pressure, you need to use Gay-Lussac's Law:

P₁ / T₁ = P₂ / T₂

In this equation, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. After converting the temperatures from Celsius to Kelvin, you can plug the given values into the equation and simplify to find P₂.

P₁ = 1.2 atm P₂ = ? atm

T₁ = 20 °C + 273 = 293 K T₂ = 35 °C + 273 = 308 K

P₁ / T₁ = P₂ / T₂ <----- Gay-Lussac's Law

(1.2 atm) / (293 K) = P₂ / (308 K) <----- Insert values

0.0041 = P₂ / (308 K) <----- Simplify left side

1.3 = P₂ <----- Multiply both sides by 308

3 0

1 year ago

Please help, I’m a bit confused, lol

Mashutka [201]

Explanation:

option A skeleton system is correct option

hope this helps you !

4 0

2 years ago